All categories

3 years ago

Q subtracted from 24×4/15 P simplified

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

3 0

Answer:

$6.4 - Q$

Step-by-step explanation:

Write it out: $\frac{24(4)}{15} - Q$
Simplify: $\frac{96}{15} - Q$
Simplify: $6.4 - Q$

I hope this helps!

You might be interested in

How do you rearrange the formula for the variable indicated:

PSYCHO15rus [73]

Watch closely. I'll try to go slow:

You said <u>v² = 2 g t</u>

Divide each side by 2g : <em>v² / 2g = t</em>

Did you follow that ?

6 0

4 years ago

PLEASE ANSWER IM GIVING OUT MOST OF MY POINTS AND ILL GIVE BRAINLIEST TO THE ONE THAT MAKES THE MOST SENSE AND IS well JUST THE

UkoKoshka [18]

Answer:

25 minutes

Step-by-step explanation:

50÷10=5

5×5=25

hopefully this helps :)

8 0

3 years ago

Read 2 more answers

A manufacturer of golf equipment wishes to estimate the number of left-handed golfers. A previous study indicates that the propo

never [62]

Answer:

A sample of 997 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

A previous study indicates that the proportion of left-handed golfers is 8%.

This means that $\pi = 0.08$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a p-value of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?

This is n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 2.327\sqrt{\frac{0.08*0.92}{n}}$

$0.02\sqrt{n} = 2.327\sqrt{0.08*0.92}$

$\sqrt{n} = \frac{2.327\sqrt{0.08*0.92}}{0.02}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.08*0.92}}{0.02})^2$

$n = 996.3$

Rounding up:

A sample of 997 is needed.

3 0

3 years ago

The drama club was selecting which carnival booths to sponsor at the fall carnival from a list of nine. How many different ways

denis-greek [22]

Answer:

Option B

Step-by-step explanation:

Here we have to apply " combination and permutation. " It is given that the drama club had to choose three booths from a selection of 9, considering the possible ways to choose so. This is a perfect example of combination. In nCr, n corresponds to 9, respectively r corresponds to 3.

$\mathrm{n\:choose\:r},\\nCr=\frac{n!}{r!\left(n-r\right)!},\\\\\frac{9!}{3!\left(9-3\right)!} =\\\frac{9!}{3!\cdot \:6!} =\\\\\frac{9\cdot \:8\cdot \:7}{3!} =\\\frac{504}{6} =\\\\84\\\\Solution = Option B$

Hope that helps!

8 0

3 years ago

Helpppppppppppppppp it is due now

Fudgin [204]

Hey mate hope its help you...

5 0

3 years ago

Read 2 more answers