What type of energy does an object gain as it is lifted at a constant speed?

A rod (length = 2.0 m) is uniformly charged and has a total charge of 5.0 nC. What is the electric potential (relative to zero a

Ksenya-84 [330]

Answer:

The electric potential is $V = 15.6 V$

Explanation:

From the question we are told that

The length of the rod is $L = 2.0 \ m$

The total charge of the rod is $q =5.0 nC = 5.0*10^{-9} C$

The length from the center is $d = 3.0 \ m$

The diagram illustrating the setup for this question is shown on the first uploaded image

From the diagram the potential at point A $dl$ is mathematically represented as

$dV = K \frac{dq}{l}$

Where K is the coulomb constant with a value $K = 9*10^9 \ Nm^2 /C^2$

where q is the charge in charge the rod relative to its distance from A is mathematically represented as

$dq = \frac{q}{L} dl$

This a small unit length of the rod

So $V = \frac{q}{L} \int\limits^4_2 {\frac{dl}{l} } \,$

=> $V = k\frac{q}{L} ln [\frac{4}{2} ]$

$V = k\frac{q}{L} ln2$

Substituting values

$V = 9* 10^9 * \frac{5*10^{-9}}{2} * ln 2$

$V = 15.6 V$

7 0

4 years ago

After a student shoves a book across a flat table, it begins to slow down. Why?

Dovator [93]

Answer:

<u>The force of friction opposes the motion of an object, causing moving objects to lose energy and slow down. When objects move through a fluid, such as air or water, the fluid exerts a frictional force on the moving object. The frictional force from a fluid is called a drag force.</u>

6 0

3 years ago

A 0.12 g honeybee acquires a charge of +24pC while flying. The earth's electric field near the surface is typically 100 N/C, dow

shusha [124]

Answer:

150000000

$\dfrac{F_e}{F_g}=0.00000203873598369$

49050000 N/C

Explanation:

q = Charge = 24 pC

m = Mass of honeybee = 0.12 g

E = Electric field = 100 N/C

g = Acceleration due to gravity = 9.81 m/s²

$1\ C=6.25\times 10^{18}\ electrons$

Number electrons is

$n=24\times 10^{-12}\times 6.25\times 10^{18}\\\Rightarrow n=150000000$

The number of electrons added or removed was 150000000

Force is given by

$F_e=Eq\\\Rightarrow F_e=100\times 24\times 10^{-12}\\\Rightarrow F_e=2.4\times 10^{-9}\ N$

The ratio is

$\dfrac{F_e}{F_g}=\dfrac{2.4\times 10^{-9}}{0.12\times 10^{-3}\times 9.81}\\\Rightarrow \dfrac{F_e}{F_g}=0.00000203873598369$

The ratio is $\dfrac{F_e}{F_g}=0.00000203873598369$

Balancing the forces we get

$Eq=mg\\\Rightarrow E=\dfrac{mg}{q}\\\Rightarrow E=\dfrac{0.12\times 10^{-3}\times 9.81}{24\times 10^{-12}}\\\Rightarrow E=49050000\ N/C$

The electric field required is 49050000 N/C

4 0

4 years ago

I think it is the third one

vekshin1

I’d go with the second one. If the solute is completely dissolved, then it’s unsaturated. If it settles out, it’s saturated. If you heat up a saturated solution and it becomes unsaturated, you have a saturated solution.

3 0

4 years ago

How much clothes should be applied on 100 cm² area using pressure of 25 Pa

IrinaVladis [17]

Answer:

hi !

Pressure = Force/Area

Force = Pressure*Area

Pressure = 25 Pa

Area = 100 cm² = 0.01 m²

F = 25*0.01

= 0.25 N

Explanation:

6 0

3 years ago