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lisabon 2012 [21]
2 years ago
9

PLEASE HELP-

Mathematics
1 answer:
Deffense [45]2 years ago
5 0

Answer:

1492.88

Step-by-step explanation:

V = πr^2 h/3

3.14 × 18^2

3.14 × 324 = 1017.36

1017.36 × 4.4 = 4476.384

4476.384 ÷ 3 = 1492.88

Hope this helped.

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Y=__X+__ ??? plz answerrr
Paul [167]

Answer:

y=3 over -6x + 5

Step-by-step explanation:

put the 3 and -6 in a fraction

4 0
3 years ago
If x+y=8, y+z=7, and x+z=5, what is the value of x? What is the formula or strategy to approach this question?
joja [24]

The strategy is to work from a system with three variables and three equations down to something with two variables and two equations. In a two variable-two equation system, you can use either substitution or elimination.

First, let's organize the equations.

(1) x + y = 8

(2) y + z = 7

(3) x + z = 5

Now, we'll solve one of (1), (2), and (3) for a variable. The choice is yours, but we'll use equation (3) and solve it for x.

x + z = 5

x = 5 - z.

Now we put this into equation (1). Why (1)? It's the only one of (1) and (2) with x.

x + y = 8

5 - z + y = 8

-z + y = 3

y - z - 3 to rearrange it.

Now look at this new equation - call it (4) and the original (2).

(4) y - z = 3

(2) y + z = 7

This is a system of two equations and two variables. Either substitution or elimination works here - let's use elimination because of the -z and +z.

y - z = 3

y + z = 7

We add them together and we have that 2y = 10. Divide on both sides and y = 5. One variable down, two to go.

Now we go back to original equation (2). Substitute y = 5 to find z.

y + z = 7

5 + z = 7

z = 2.

Two down, one to go. Since we know z = 2, let's put it into (3) and find x. (Equation (1) with y = 5 works fine as well.)

x + z = 5

x + 2 = 5

x = 3

Thus x = 3, y = 5 and z = 2.

3 0
3 years ago
Can anyone help? It’s not 14, I’ll give Brainly + 15 pts
Julli [10]

Short side length = x

Medium side = x + 7

Long side = 5x

Total 49, so

x + x + 7 + 5x = 49

If you combine like terms:

7x + 7 = 49

Subtract 7 from both sides

7x = 42

Divide both sides by 7

x = 6 inches.

8 0
2 years ago
Find a nonzero vector orthogonal to the plane through the points: ????=(0,0,1), ????=(−2,3,4), ????=(−2,2,0).
ser-zykov [4K]

Answer:

The nonzero vector orthogonal to the plane is <-9,-8,2>.

Step-by-step explanation:

Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).

\overrightarrow {PQ}==

\overrightarrow {PR}==

The nonzero vector orthogonal to the plane through the points P,Q, and R is

\overrightarrow n=\overrightarrow {PQ}\times \overrightarrow {PR}

\overrightarrow n=\det \begin{pmatrix}i&j&k\\ \:\:\:\:\:-2&3&3\\ \:\:\:\:\:-2&2&-1\end{pmatrix}

Expand along row 1.

\overrightarrow n=i\det \begin{pmatrix}3&3\\ 2&-1\end{pmatrix}-j\det \begin{pmatrix}-2&3\\ -2&-1\end{pmatrix}+k\det \begin{pmatrix}-2&3\\ -2&2\end{pmatrix}

\overrightarrow n=i(-9)-j(8)+k(2)

\overrightarrow n=-9i-8j+2k

\overrightarrow n=

Therefore, the nonzero vector orthogonal to the plane is <-9,-8,2>.

8 0
3 years ago
Pls heelp me it will mean alot to me <br>im just tryna finish high school
Rudiy27

Answer:

infinite many

Step-by-step explanation:

5 0
3 years ago
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