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2 years ago

What values of a and b make the equation true?

Mathematics

1 answer:

iogann1982 [59]2 years ago

4 0

Answer:

O a = 3, b = 4

Step-by-step explanation:

plug the values in the equation

please mark brainliest

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This is the other post, ill give brainlist to the best answer.<br>

snow_tiger [21]

Step-by-step explanation: 1 will now become a 2, so the answer is 1.2.1,

6 0

3 years ago

Please, I need help in this ??

nignag [31]

Answer:

$\int\frac{x^{4}}{x^{4} -1}dx = x + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1)-\frac{1}{2} arctanx + c$

Step-by-step explanation:

$\int\frac{x^{4}}{x^{4} -1}dx$

Adding and Subtracting 1 to the Numerator

$\int\frac{x^{4} - 1 + 1}{x^{4} -1}dx$

Dividing Numerator seperately by $x^{4} - 1$

$\int 1 + \frac{1}{x^{4}-1 }\, dx$

Here integral of 1 is x +c1 (where c1 is constant of integration

$x + c1 + \int\frac{1}{(x-1)(x+1)(x^{2}+1)}\, dx$ ----------------------------------(1)

We apply method of partial fractions to perform the integral

$\frac{1}{(x-1)(x+1)(x^{2}+1)}$ = $\frac{A}{x-1} + \frac{B}{x+1} + \frac{C}{x^{2} + 1}$ ------------------------------------------(2)

$\frac{1}{(x-1)(x+1)(x^{2}+1)} = \frac{A(x+1)(x^{2} +1) + B(x-1)(x^{2} +1) + C(x-1)(x+1)}{(x-1)(x+1)(x^{2} +1)}$

1 = $A(x+1)(x^{2} +1) + B(x-1)(x^{2} +1) + C(x-1)(x+1)$ -------------------------(3)

Substitute x= 1 , -1 , i in equation (3)

1 = A(1+1)(1+1)

A = $\frac{1}{4}$

1 = B(-1-1)(1+1)

B = $-\frac{1}{4}$

1 = C(i-1)(i+1)

C = $-\frac{1}{2}$

Substituting A, B, C in equation (2)

$\int\frac{x^{4}}{x^{4} -1}dx$ = $\int\frac{1}{4(x-1)} - \frac{1}{4(x+1)} -\frac{1}{2(x^{2}+1) }$

On integration

Here $\int \frac{1}{x}dx = lnx and \int\frac{1}{x^{2}+1 } dx = arctanx$

$\int\frac{x^{4}}{x^{4} -1}dx$ = $\frac{1}{4} ln(x-1)$ - $\frac{1}{4} ln(x+1)$ - $\frac{1}{2} arctanx$ + c2---------------------------------------(4)

Substitute equation (4) back in equation (1) we get

$x + c1 + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1) - \frac{1}{2} arctanx + c2$

Here c1 + c2 can be added to another and written as c

Therefore,

$\int\frac{x^{4}}{x^{4} -1}dx = x + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1)-\frac{1}{2} arctanx + c$

4 0

3 years ago

You save for retirement over 30 years by investing $850/month in a stock account that yields 10%. You invest $350/month in a bon

sergejj [24]

Answer:

$13,287.70

Step-by-step explanation:

The future value of the stock account is computed as the sum of a geometric series. This computation assumes that the annual yield is compounded monthly.

FV = p((1+r/12)^(12n) -1)/(r/12)

For the stock account, p=850, r=0.10, n=30, so the future values is ...

FV = 850((1+.10/12)^360-1)/(.10/12)) = 1,921,414.74

For the bond account, p=350, r=.06, n=30, so the future value is ...

FV = 350((1+.06/12)^360 -1)/(.06/12) = 351,580.26

The combined account value at the end of 30 years is ...

$1,921,414.74 + 351,580.26 = $2,272,995.00

_____

The monthly payment that can be made over a 25 year period is given by the amortization formula.

A = P(r/12)/(1 -(1 +r/12)^(-12n))

= $2,272,995.00(.05/12)/(1 -(1+.05/12)^-300) = $13,287.70

You can withdraw $13,287.70 each month assuming a 25-year withdrawal period.

6 0

3 years ago

Find x: 2(4x − 3) − 8 = 4 + 2x

MariettaO [177]

X = 3

2(4x - 3) - 8 = 4 + 2x

1. Distribute

8x - 6 - 8 = 4 + 2x

2. Collect like terms

8x - 14 = 4 + 2x

3. Collect like terms again (add 14 and subtract 2x)

6x = 18

4. Divide by 6

x = 3

4 0

3 years ago

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2 years ago