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marishachu [46]
3 years ago
9

What’s 44x10=to the 0 power

Mathematics
1 answer:
user100 [1]3 years ago
4 0

Answer:

1

Step-by-step explanation:

Simplify the following:

(44×10)^0

Hint: | Simplify (44×10)^0 by distributing exponents over products.

Multiply each exponent in 44×10 by 0:

Answer: 1

any number to the zero power always gives a one

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Find the slope of the line that passes through the points f(4) = 6 and f(-2) = 8.
leonid [27]

Answer:

slope = - \frac{1}{3}

Step-by-step explanation:

given f(4) = 6 and f(- 2) = 8 , then 2 points on the line are

(4, 6 ) and (- 2, 8 )

calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (4, 6 ) and (x₂, y₂ ) = (- 2, 8 )

m = \frac{8-6}{-2-4} = \frac{2}{-6} = - \frac{1}{3}

6 0
2 years ago
ASAP HELP!!! use the quadratic regression feature of a graphing calculator to find a quadratic model. round to the nearest thous
seropon [69]

Answer:

y = 0.008x^2 + 0.518x + 131.886

Step-by-step explanation:

  1. Make sure your Plot 1 is ON. Select the Scatter Plots and the appropriate lists.
  2. Clear all functions in [Y=]
  3. Input data in L1 and L2. Go to [Stat] [Enter] to input data.
  4. Graph data points. ...
  5. Choose a regression from the list in [Stat] "CALC". ...
  6. Go to [ZOOM] "9: ZoomSTat" to view the data with the regression curve.

(credit: CPM Educational Program)

3 0
3 years ago
Please help using law of cosines!
Tamiku [17]

Answer:

∠ A ≈ 48°

Step-by-step explanation:

Using the Cosine rule to find an angle

cosA = \frac{b^2+c^2-a^2}{2bc}

with a = 10, b = 13 and c = 11

cosA = \frac{13^2+11^2-10^2}{2(13)(11)}

         = \frac{169+121-100}{286}

         = \frac{190}{286} , thus

A = cos^{-1} ( \frac{190}{286} ) ≈ 48° ( to the nearest degree )

6 0
4 years ago
A cable company wants to provide cell phone service for residents on an island. The function for the cost of laying the cable fr
laila [671]

Answer:

C) domain: all real numbers greater than or equal to 0

range: all real numbers greater than or equal to 13,000

Step-by-step explanation:

We have, the function for the cost of laying cable is given by,

c(x)= 6500\sqrt{x^2+4}, where x is the length of the cable (in feet).

As, 'x' represents the length of the cable.

We have that, the value of x cannot be negative.

So, x ≥ 0.

Since, the domain of c(x)= 6500\sqrt{x^2+4} is the set of points where x^2+4\geq 0 and we have that x ≥ 0.

Thus, the domain is 'Set of all real numbers greater than or equal to 0'.

Now, we substitute x= 0 in c(x)= 6500\sqrt{x^2+4}.

i.e. c(0)= 6500\sqrt{0^2+4}

i.e. c(0)= 6500\sqrt{4}

i.e. c(0)= 6500\times 2

i.e. c(0) = 13000.

So, we get that the vertex point of the function is (0,13000).

Thus, the range is 'All real numbers greater than or equal to 13,000'.

5 0
3 years ago
Read 2 more answers
X-cubed+3x-squared+5x+8/x+1
Blababa [14]
X^3+3x^2+5x+8/x+1
multiply the whole equation by x
x^4+3x^3+5x^2+8+1x
x^4+3x^3+5x^2+x+8
factor out by parts
(x^2-0.641604x+1.33244)(x^2+3.6416x+6.00403)
4 0
3 years ago
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