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Soloha48 [4]
2 years ago
6

WIL MARK BRAINLYEST !

Mathematics
2 answers:
pantera1 [17]2 years ago
8 0

Answer:

0.2, 0.25, 21% 87%

Though i am not entirely sure because the percentages specify where the percent is coming from.

Tcecarenko [31]2 years ago
6 0

Answer:

87%>0.25>21%>0.2

Step-by-step explanation:

87% converted to decimal form is 0.87 which is greater than 0.25 and 21% converted to decimal form is 0.21 which is also greater than 0.2 which can also be interpreted as 0.20! Hope this helps!

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Complete the pattern—- 9.5 950 95,000 —- ——
victus00 [196]

Answer:

  9,500,000  950,000,000

Step-by-step explanation:

Each number is 100 times the previous. Basically, add 2 zeros to get the next number.

  • 9.5
  • 950
  • 95,000
  • 9,500,000
  • 950,000,000
6 0
3 years ago
Select all statements that show correct reasoning for finding 15 = 3
mario62 [17]

Answer:

. Multiply 15 by 1, then divide by 5

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2 years ago
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What is the gcf for 3 and 7
GaryK [48]

Answer:

The gcf of 3 and 7 is 1.

Step-by-step explanation:

6 0
3 years ago
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Simplify the expression:<br><br> 4(9p + 1)
Tju [1.3M]

Answer:

36p+4

Step-by-step explanation:

4 0
2 years ago
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A mass of 5 kg stretches a spring 10 cm. The mass is acted on by an external force of 10sin( t ) N(newtons) and moves in a mediu
yKpoI14uk [10]

Answer:

A) C1 = 0.00187 m = 0.187 cm,  C2 = 0.0062 m = 0.62 cm

B)  A sample of how the graph looks like is attached below ( periodic sine wave )

C) w = \sqrt[4]{3} is when the amplitude of the forced response is maximum

Step-by-step explanation:

Given data :

mass = 5kg

length of spring = 10 cm = 0.1 m

f(t) = 10sin(t) N

viscous force = 2 N

speed of mass = 4 cm/s = 0.04 m/s

initial velocity = 3 cm/s = 0.03 m/s

Formulating initial value problem

y = viscous force / speed = 2 N / 0.04 m/s = 50 N sec/m

spring constant = mg/ Length of spring = (5 * 9.8) / 0.1 = 490 N/m

f(t) = 10sin(t/2) N

using the initial conditions of u(0) = 0 m and u"(0) = 0.03 m/s to express the equation of motion

the equation of motion = 5u" + 50u' + 490u = 10sin(t/2)

A) finding the solution of the initial value

attached below is the solution and

B) attached is a periodic sine wave replica of how the grapgh of the steady state solution looks like

C attached below

3 0
3 years ago
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