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guapka [62]
3 years ago
10

On a piece of paper, use a protractor and a ruler to construct △ABC with AB=4 in., AC=4 in., and m∠A=60°.

Mathematics
2 answers:
ollegr [7]3 years ago
6 0

Answer:

BC 4 in

Step-by-step explanation:

The steps for construction;

  • Using a ruler draw line AB 4 inches  and label the end points A and B
  • At point A , using a protractor, measure angle 60° and mark with point. Draw a line from A passing through this point extending to a length of 4 inches
  • Mark that point C.
  • Using the ruler, join point C and B and measure BC.

From calculation, length BC can be found by the formula;

BC=\sqrt{a^2+b^2-2*a*b*cosA}------where a=b=4 in , cos A = cos 60°

BC=\sqrt{4^2+4^2-2*4*4*cos60}

BC = 4 in

mylen [45]3 years ago
5 0

Answer:

bc = 4

Step-by-step explanation:

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seropon [69]
<h3>Answer: 5/51</h3>

======================================================

Explanation:

We have 6 green out of 6+6+6 = 18 total

The probability of getting green is 6/18 = 1/3.

After selecting that green jelly bean and not putting it back, we have 6-1 = 5 green out of 18-1 = 17 total.

The probability of selecting another green is 5/17.

Multiply the two fractions 1/3 and 5/17

(1/3)*(5/17) = (1*5)/(3*17) = 5/51

The probability of selecting two greens in a row is 5/51 where we do not put the first selection back. We also do not replace the green jelly bean with some other identical copy.

Note: 5/51 = 0.098039 approximately

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3 years ago
Don't get this question
solniwko [45]

Answer:

17 and 18

Step-by-step explanation:

Writing every 2 digit number gives us :

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For the first one we are looking for numbers where the number 3 appears only once so 33 would be invalid.

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There are 17 2-digit numbers that have 3 exactly once

For the second one we are looking for number where the number 3 appears a minimum of once so 33 would be valid :

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There are 18 2-digit numbers that have 3 at least once

Hope this helped and have a good day

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The correct answer is C. i think
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