Like a wet sponge, soil already saturated from previous rainfall can't absorb much more ... thus more rainfall will become surface runoff.
Vary in the number of neutrons but Sama in the number if protons are called isotopes
Answer:
Probability that both cats described will have an offspring who is heterozygous for both traits is 50%, according to the scenario given.
Explanation:
When a cat amazing and bashful is crossed with a cat average and boring, it is a crossing where two traits are taken into account that will be segregated independently by the parents, and the result can be obtained by analyzing their genotypes and making the corresponding crossing in a Punnett square.
<u>Genotypes</u>:
- <u>Male cat</u> AABb
- <u>Female cat
</u> aabb
<u>Crossing</u>
:
Punnett's square (simplified)
<em>Alelles AB Ab</em>
<em>ab AaBb Aabb</em>
<em>ab AaBb Aabb</em>
<u>Offspring</u>:
- <em>AaBb amazing and bashful (heterozygous for two traits) 50%</em>
- <em>Aabb amazing and boring (heterozygous for trait A ans homozygous recessive for B) 50%</em>
<u><em>Probability that they will have an offspring who is heterozygous for both traits is 50%.</em></u>
If you’re referring to the current Coronavirus pandemics, the reasons we want to mass vaccinate the population is to stop the spread by making it harder to find a host that it can use to replicate. The more times the RNA virus replicates, the more mutations are generated, the more likely a strain, that can escape the any immunity developed, can occur. Herd Immunity is what will help reduce the ability of a virus to spread. If the virus can’t find a host to replicate in (because the host is immune to the virus) the harder it is for the virus to spread.
Answer:
There you have it. Jill's parents are IAi & IB
Explanation:
one brother: Type B, one of the parents must have the IB allele
other brother: Type A,
other parent must have the IA allele & have a genotype of IAi.
Jill's parents are IAi & IB
