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aleksandrvk [35]
3 years ago
15

club a raised $168 by washing 42 cars. club b raised $152 by washing 38 cars. are these fundraising rates equivalent ? explain y

our reasoning.​
Mathematics
1 answer:
uysha [10]3 years ago
6 0

Answer:

The two rates are equivalent.

Step-by-step explanation:

Here we'll find the respective unit rates and then compare those rates:

$168

----------- = $4/car

42 cars

$152

----------- = $4/car

38 cars

These two rates are precisely the same.  Thus, we conclude that they are equivalent.

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b. Calculate the monthly payments and total payment you will be making on your loan if you do use the $5,000 to make an initial
arsen [322]

Answer:

Read the excerpt from "Digging"The cold smell of potato mould, the squelch and slapOf soggy peat, the curt cuts of an edgeThrough living roots awaken in my head.But I’ve no spade to follow men like them.Between my finger and my thumbThe squat pen rests.I’ll dig with it.Read the haiku by Bashō.     When the winter chrysanthemums go,there’s nothing to write about     but radishes.What common concern do these poems share?

Step-by-step explanation:

Read the excerpt from "Digging"The cold smell of potato mould, the squelch and slapOf soggy peat, the curt cuts of an edgeThrough living roots awaken in my head.But I’ve no spade to follow men like them.Between my finger and my thumbThe squat pen rests.I’ll dig with it.Read the haiku by Bashō.     When the winter chrysanthemums go,there’s nothing to write about     but radishes.What common concern do these poems share?

8 0
2 years ago
help asap! Write an expression equivalent to [5x²]-[15x] that is a product of two expressions. Fill in the blanks with numbers,
adoni [48]

Answer: 5x (x-3) or 5(x^2-3x)

Step-by-step explanation:

3 0
3 years ago
1. Write out the law of cosines and find the hypotenuse of triangle with 2 sides lengths equal to three and the included angle m
LUCKY_DIMON [66]

Answer:

1.) \sqrt{13.341}  ≈ 3.652

2.) I would say something about how the A in front of cos in the equation would change to 90, rather than stay 75 (in the equation for the step by step), but it would be easier to just use the Pythagorean theorem.

Step-by-step explanation:

I think we may have the same class so hopefully this helps:

1.) a^2 = b^2 + c^2 - 2bccosA --> law of cosines formula.

   a^2 = 3^2 + 3^2 - 2(3)(3)cos(75) --> plugged in numbers; when you draw the triangle, the included angle would be A, and the opposite side would be a. B and b, and C and c are opposite each other. In this case, a is the hypotenuse.

   a^2 = 18 - 18cos75 --> in between steps.

   a^2 = 13.341 --> more simplifying.

   a(hypotenuse) = \sqrt{13.341} or 3.652 --> answer

2.) This one is just an explanation: The 75 in the equation is the given angle, which is a. If this changes, it would just change in the equation too. And obviously, if it's 90 degrees, you can just use Pythagorean theorem a^2+b^2=c^2.

Good luck! :)

   

6 0
3 years ago
What is m^-1 <br><br> answer fast
mart [117]

-m

One times itself but as a negative.

6 0
3 years ago
An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref
hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}

So the cost of laying pipe under water with this distance is

800000\sqrt{(3 - d)^2 + 4}

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

800000\sqrt{(3 - d)^2 + 4} + 400000d

We can find the minimum value of this by taking the 1st derivative and set it to 0

800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0

We can move the first term over to the right hand side and divide both sides by 400000

1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}

\sqrt{(3 - d)^2 + 4} = 6 - 2d

From here we can square up both sides

(3 - d)^2 + 4 = (6 - 2d)^2

9 - 6d + d^2 + 4 = 36 - 24d + 4d^2

3d^2-18d+27 = 0

d^2 - 6d + 9 = 0

(d - 3)^2 = 0

d -3 = 0

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0
3 years ago
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