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nataly862011 [7]

3 years ago

13

a student is running 5-km race. He runs 1km every 3 min. Select the function that describes his distance from the finish line x

minutes.

1 answer:

Juli2301 [7.4K]3 years ago

3 0

$3x=time$

x is the distance

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Express {x+1}{2x-3} as a trinomial.

Marizza181 [45]

Answer:

$2x^2 + 5x + 3$

Step-by-step explanation:

First, expand the original equation:

(x + 1)(2x + 3)

$2x^2 + 3x + 2x + 3$

Now simplify:

$2x^2 + 5x + 3$

And that's your answer!

6 0

3 years ago

Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$

Since

$\int\limits^1_0 {x^{2} } \, dx = 13$ ,

Substituting this into the equation the equation, we have

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Learn more about definite integrals here:

brainly.com/question/17074932

4 0

2 years ago

How do you do number 20?

LenKa [72]

The answer isnin the pictures

4 0

3 years ago

Find an angle between 0 and 2 that is coterminal with the given angle.

galben [10]

Answer:

40degres

Step-by-step explanation:

4 0

3 years ago

Find the area. Use 3.14 for the value of pi. Round your answer to the nearest tenth. diameter = 14 yd

sergij07 [2.7K]

A=pi(radius)^2

Radius=Diameter/2

Radius= 14/2=7yds

A=3.14(7)^2

A=153.86yds

8 0

3 years ago

Read 2 more answers