3. Use the Babylonian method to approximate √19 to the nearest hundredth.

Mathematics

1 answer:

Scrat [10]3 years ago

6 0

The square root of 19 is 4.36 when rounded to the nearest hundredth

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HELP!!! There is a photo please quickly!!

Nostrana [21]

Answer:

∆y = 9

∆x = 6

Slope = 3/2 or 1.5

It looks like you erased it, but you had the answer correct on your paper.

Step-by-step explanation:

7 0

1 year ago

Use CALCULUS to find coordinates of the turning point on C.

antiseptic1488 [7]

Oi

Just calculating the differential. Step by step:

$y=12 \sqrt{x} -x \frac{3}{2}-10 \\ \\ y=12x^{ \frac{1}{2} } -x \frac{3}{2}-10 \ \ \ \boxed{transform \ \sqrt{x} =x^{ \frac{1}{2} }} \\ \\ Differentiating \\ \\ y'=12. \frac{1}{2}.x^{ \frac{1}{2}-1 } -1.x^{1-1}. \frac{3}{2}-0 \\ \\ y'=6.x^{ -\frac{1}{2} } -x^{0}. \frac{3}{2} \\ \\ y'=6. \frac{1}{x^{ \frac{1}{2} }} -1. \frac{3}{2} \\ \\ \boxed{y'=\frac{6}{ \sqrt{x} } -\frac{3}{2}}$

If you want to know where the tangent has no slope:

$\frac{6}{ \sqrt{x} } - \frac{3}{2} =0 \\ \\ \frac{6}{ \sqrt{x} } = \frac{3}{2} \\ \\ 3 \sqrt{x} =12 \\ \\ \sqrt{x} = \frac{12}{3} \\ \\ \sqrt{x} =4 \\ \\ (\sqrt{x})^2 =4^2 \\ \\ x=16$

3 0

3 years ago

What is the slope of the line shown below

gizmo_the_mogwai [7]

Answer:

A. 4

Step-by-step explanation:

1. Use the SLOPE FORMULA: M= rise/run= y2-y1/x2-x1

2. Plug in the two coordinates that were plotted on the equation: (1,1) & (3,9)

3. Label the coordinates

( 1 , 1 ) = ( x1, y1 )& ( 3, 9 ) = ( x2, y2 )

4. SOLVE & PLUG IN