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bija089 [108]
3 years ago
8

Form a union for the following sets. M = {1, 2, 4, 8) N = (2,5,8)

Mathematics
2 answers:
inna [77]3 years ago
8 0

Answer:

H hcicucuckvjlzfjgixhdjvgkzkgv

Step-by-step explanation:

Dulfhoxfxcyxg yxyfyofucuffuocofoduucuoxugxyodoyy

ELEN [110]3 years ago
7 0

Answer:

Step-by-step explanation:

When you are asked to find the union of sets you find numbers that are present in both sets.

So a number that appears in both the sets of M and N are 2 and 8.

So M U N = { 2,8} where U is the symbol for union.

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A cube has a volume of 125 cubic inches. What is the length of each edge?
goldenfox [79]

Answer:

5

Step-by-step explanation:

5 time 5 is 25

25 time 5 is 125

4 0
3 years ago
Read 2 more answers
Which of the following expressions is equivalent to the expression below 4(2x+11-x)
zubka84 [21]
4(2x+11-x)
4(2x-x)
4(1x+11)
4x+44
7 0
4 years ago
PLZ HELP GUYS...AND PLZ TRY LOL... BRAINLIEST ANSWER FOR WHO IS CORRECT ;)
lyudmila [28]

Answer:  like terms are 17c and 10c, 3d and d

17c + 10c=27c

Step-by-step explanation:−3d−17c+10c−d

=−3d+−17c+10c+−d

Combine Like Terms:

=−3d+−17c+10c+−d

=(−17c+10c)+(−3d+−d)

=−7c+−4d

7 0
4 years ago
Can someone help me out with some pesky math quiz :) I put a pic
Sindrei [870]

1. Simplifying ∛54 gives 3∛2

2. 27^1/3 * (27)^3 is equal to  27

3. The expression (2j4k)^4/5 can be written as \sqrt[4]{32j^{20}k^{5}  }^{5} making the first option the correct option

4. simplifying \sqrt[4]{16x^{4} y^{12} } will result to 2x∛y

5. simplifying \sqrt[5]{2940x^{13} y^{7} } will result to 14x^{6} y^{3} \sqrt{15xy} making the last option the correct option

<h3>How to simplify \sqrt[5]{2940x^{13} y^{7} }</h3>

<u>given data</u>

\sqrt[5]{2940x^{13} y^{7} }

= ( 2940 * x^13 * y^7 )^1/5

=  ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5}

=  ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5*5/2}

=  ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{5/5*1/2}

multiplying the values inside the parenthesis by ^1/2

= ( 2 * 5^{1/2} * 3^{1/2} * 7 * x^{6} * x^{1/2} * y^3 * y^{1/2} )

= ( 2 * 5^{1/2} * 3^{1/2} * 7 * x^{6} * x^{1/2} * y^3 * y^{1/2} )

= ( 14* 5^{1/2} * 3^{1/2} * x^{6} * x^{1/2} * y^3 * y^{1/2} )

= ( 14 * x^6 * y^3 ) ( 5^{1/2} * 3^{1/2}  * x^{1/2} * y^{1/2} )

= ( 14x^6y^3 ) ( 15^{1/2} * x^{1/2} * y^{1/2} )

= ( 14x^6y^3 ) ( 15xy)^{1/2}

= ( 14x^6y^3 ) \sqrt{( 15xy)}

we can therefore say that the last option is the answer

Read more on equations here: brainly.com/question/22688504

#SPJ1

3 0
1 year ago
Need help as soon as possible
nadya68 [22]
525. You need to take 14×27+7×3+14×9. That equals 525.
6 0
3 years ago
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