The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Answer:
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Step-by-step explanation:
Let Kat reads k pages of the book.
Miguel reads 5 times as many pages of the book as Kat. So,
m = 5k ...(1)
Together they read 54 pages. i.e.
m+k = 54 ...(2)
From equation (1),
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Hence, the equation that can be used to find how many pages Kat read is equal to
.
Answer:2.3 or 2.38
Step-by-step explanation:
I know
Step-by-step explanation:
ofc , so that is that and the other is that
Need to see the picture ..?