Eight subtracted from four times a number is -120?
2 answers:
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The average rate of change over a given interval is the slope of the secant line through the endpoints of the interval.
![m = \dfrac{f(b)-f(a)}{b-a} = \dfrac{f(103)-f(100)}{103-100}\\\\ = \dfrac{(103)^2-2500-[(100)^2-2500]}{103-100} = \dfrac{609}{3}=203](https://tex.z-dn.net/?f=m%20%3D%20%5Cdfrac%7Bf%28b%29-f%28a%29%7D%7Bb-a%7D%20%3D%20%20%5Cdfrac%7Bf%28103%29-f%28100%29%7D%7B103-100%7D%5C%5C%5C%5C%20%3D%20%5Cdfrac%7B%28103%29%5E2-2500-%5B%28100%29%5E2-2500%5D%7D%7B103-100%7D%20%3D%20%20%5Cdfrac%7B609%7D%7B3%7D%3D203)
$203/unit.
The instantaneous rate of change at a certain point is the slope of the tangent line.
We differentiate C to get 2x. We substitute 100 for x to get that the instantaneous rate of change at 100 is $200/unit.
$203/unit.
The instantaneous rate of change at a certain point is the slope of the tangent line.
We differentiate C to get 2x. We substitute 100 for x to get that the instantaneous rate of change at 100 is $200/unit.
Answer:
Step-by-step explanation:
Let l be the length and w be the width of the rectangle
Given:
The length of the rectangle is 4 meters more than the width.
The length of the rectangle is
The perimeter of the rectangle should be less than 100 meters.
The perimeter of the rectangle is and it is less than 100 m.
So, the equation is.
Put length of the rectangle in above equation.
Therefore, the inequality expresses all of the possible widths is