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4 years ago

13

A simple random sample of 85 is drawn from a normally distributed population, and the mean is found to be 146, with a standard d

eviation of 34. Which of the following values is outside the 99% confidence interval for the population mean?

2 answers:

omeli [17]4 years ago

8 0

Answer:

anything below 136.5 or above 155.5

Step-by-step explanation:

the critical value from a Z distribution for the 99% confidence level is 2.576

so we just need to compute

146 + 2.576(34/sqrt(85))

and

146 + 2.576(34/sqrt(85))

Assoli18 [71]4 years ago

7 0

Answer:

<em>A. the value of 135 because it is not greater than 136.5</em>

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The monthly cost (in dollars) of a long-distance phone plan is a linear function of the total calling time (in minutes). The mon

kkurt [141]

The monthly cost will be $17.14

Step-by-step explanation:

Given that the monthly cost (in dollars) of a long-distance phone plan is a linear function of the total calling time (in minutes) then this can be presented in a table form as;

<u>Time in minutes (x)</u> <u>Cost in dollars (y)</u>

50 $12.55

102 $ 17.23

Take the values as ordered pairs to represent coordinates for points that satisfy the linear function

(50,12.55) and (102,17.23)

Finding the slope of the graph using these points

slope,m=Δy/Δx

m=Δy=17.23-12.55 =4.68

Δx=102-50=52

m=4.68/52 =0.09

Finding the equation of the linear function using m=0.09, and point (50,12.55)

m=Δy/Δx

0.09=y-12.55/x-50

0.09(x-50)=y-12.55

0.09x-4.5=y-12.55

0.09x-4.5+12.55=y

y=0.09x+8.05

So for 101 minutes , the cost will be;

y=0.09*101 +8.05

y=9.09+8.05 = $17.14

Learn More

Linear functions : brainly.com/question/11052356

Keyword : linear function

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5 0

4 years ago

Find the volume of the solid generated by revolving the region enclosed by the triangle with vertices (1 comma 0 ), (3 comma 2

Troyanec [42]

Answer: Volume = $\frac{20\pi }{3}$

Step-by-step explanation: The <u>washer</u> <u>method</u> is a method to determine volume of a solid formed by revolving a region created by any 2 functions about an axis. The general formula for the method will be

V = $\pi \int\limits^a_b {(R(x))^{2} - (r(x))^{2}} \, dx$

For this case, the region generated by the conditions proposed above is shown in the attachment.

Because it is revolting around the y-axis, the formula will be:

$V=\pi \int\limits^a_b {(R(y))^{2} - (r(y))^{2}} \, dy$

Since it is given points, first find the function for points (3,2) and (1,0):

m = $\frac{2-0}{3-1}$ = 1

$y-y_{0} = m(x-x_{0})$

y - 0 = 1(x-1)

y = x - 1

As it is rotating around y:

x = y + 1

This is R(y).

r(y) = 1, the lower limit of the region.

The volume will be calculated as:

$V = \pi \int\limits^2_0 {[(y+1)^{2} - 1^{2}]} \, dy$

$V = \pi \int\limits^2_0 {y^{2}+2y+1 - 1} \, dy$

$V=\pi \int\limits^2_0 {y^{2}+2y} \, dy$

$V=\pi(\frac{y^{3}}{3}+y^{2} )$

$V=\pi (\frac{2^{3}}{3}+2^{2} - 0)$

$V=\frac{20\pi }{3}$

The volume of the region bounded by the points is $\frac{20\pi }{3}$ .

6 0

4 years ago

6. Complete: (ref.p.290)<br> a. 18 ft ..............d<br> b. 6.5c =.......................fl. oz

sashaice [31]

Answer:

a) What is d?

b) 52fl.oz

6 0

3 years ago

Which set of fractions is ordered from greatest to least? A two over three, three over eight, five over twelve B five over twelv

Annette [7]

Answer:

When ordering three or more fractions from least to greatest, compare two fractions at a time. It is helpful to write a number in a circle next to each fraction to compare them more easily.

6 0

3 years ago

TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital streamin

oksian1 [2.3K]

Answer:

The 99% confidence level for the proportion of all adult Americans who watched streamed programming up to that point in time is (0.514, 0.566). This means that we are 99% sure that the true proportion of all American adults surveyed said they have watched digitally streamed TV programming on some type of device is between 0.514 and 0.566.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

A poll reported that 54% of 2342 American adults surveyed said they have watched digitally streamed TV programming on some type of device.

This means that $\pi = 0.54, n = 2342$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a p-value of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.54 - 2.575\sqrt{\frac{0.54*0.46}{2342}} = 0.514$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.54 + 2.575\sqrt{\frac{0.54*0.46}{2342}} = 0.566$

The 99% confidence level for the proportion of all adult Americans who watched streamed programming up to that point in time is (0.514, 0.566). This means that we are 99% sure that the true proportion of all American adults surveyed said they have watched digitally streamed TV programming on some type of device is between 0.514 and 0.566.

6 0

3 years ago