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Naily [24]
4 years ago
13

A simple random sample of 85 is drawn from a normally distributed population, and the mean is found to be 146, with a standard d

eviation of 34. Which of the following values is outside the 99% confidence interval for the population mean?
Mathematics
2 answers:
omeli [17]4 years ago
8 0

Answer:

anything below 136.5 or above 155.5

Step-by-step explanation:

the critical value from a Z distribution for the 99% confidence level is 2.576

so we just need to compute

146 + 2.576(34/sqrt(85))

and

146 + 2.576(34/sqrt(85))

Assoli18 [71]4 years ago
7 0

Answer:

<em>A. the value of 135 because it is not greater than 136.5</em>

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4 years ago
Find the value of the following expression below 8(15-4)/4^2-5
Sonja [21]

Answer:

The correct answer is 1/2 or 0.5

Step-by-step explanation:


8(15-4)/4^2-5

8(11)/4^2-5

Now i'm going to multiply 8 by 11

88/4^2-5

Now solve 4^2

Which is 16.

Now we have 88/16-5

Divide 88 and 16 which is 5.5.

Now minus 5.5 - 5 which gets us our answer: 0.5


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4 years ago
Given the equation 4x + 7 = 3(2x − 5), solve for the variable. Explain each step and justify your process.
MariettaO [177]
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5 0
3 years ago
Coffee sells for $5 per pound. If a farmer sells 12,000,000 pounds of coffee, how much money will the farmer make?
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4 0
4 years ago
Read 2 more answers
A box contains 4 oranges, 9 apples, and 3 pears. Liliana selects a piece of fruit from the box at random. What is the probabilit
valina [46]
Hello!

You first find out how many objects there are in total


4 + 9 + 3 = 16

Then you find the probability of Liliana picking a orange

Since there are 4 oranges and 16 things to pick she has a 4/16 chance of getting an orange

Next you find the probability of Liliana picking a pear

There are 3 pears and 16 items to pick so she has a 3/16 chance

Then you add them together to find the chance of either happening

4/16 + 3/16 = 7/16

So she has a 7 out of 16 chance of getting an orange or a pear

The answer is 7/16

Hope this helps!
3 0
3 years ago
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