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slamgirl [31]
3 years ago
13

Solve: 3x = 9 help me please

Mathematics
1 answer:
docker41 [41]3 years ago
4 0

Answer:

=3

Step-by-step explanation:

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A spinner used in a board game is divided into 12 equally sized sectors. Seven of these sectors indicate that the player should
xeze [42]

Answer:

20.8 inches squared

Step-by-step explanation:

Area of spinner:

45.1 is the area of sectors where the token doesn't move, which 5 sectors doesn't move the token (don't forget that the bonus points doesn't move token). Then

45.1/5=9.02

9.02*12=108.24

K=1/2(r^2)sin150

108.24=1/2(r^2)sin150

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r=20.8

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4 years ago
What should be added to 8 to make the sum 0
Mars2501 [29]
-8 because when you add a negative number your basically subtracting its absolute value.
3 0
3 years ago
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It costs 4 tokens to park in a garage for an hour. how many hours can you park with 30 tokens?
babunello [35]

Read the question carefully: it costs 4 tokens to park in a garage for an hour.

We will apply the unitary method to solve this question

It costs 4 tokens to park in a garage for 1 hour

Find how many hours can park in a garage for 1 token

If it costs 4 token to park in a garage for 1 hour

Then it will cost 1 token to park in a garage for 1/4 hour

Step2:

With 20 token we can park in a garage for (1/4) * 20

= 5 hours

So, we can park for 5 hours with 20 tokens.

Another method

If we take twenty tokens and divide them into groups of four, we will find that we are left with five groups of tokens. Each group of tokens represents an hour of parking time. This will give us five groups, or five hours, total.

So, we can park for 5 hours with 20 tokens
5 0
3 years ago
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For the equation 3(2x − 5) = 6x + k, which value of k will create an equation with infinitely many solutions?
lana [24]

Answer: K = -14

Step-by-step explanation: solve for k by simplifying both sides of the equation then isolating the variable

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3 years ago
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Please help me with this question I’m stuck!
Natasha_Volkova [10]
12 is the answer.

The sequence is 12, 6, 3, 3/2
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4 years ago
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