What is the vertex of the function f(x) = x2 + 12x?
1 answer:
We can start by figuring out the axis of symmetry.
y = x² + 12x = x (x + 12)
So roots are x = -12 or 0
Therefore axis of symmetry is x = (-12 + 0) / 2 = -6
We got x-coordinate of vertex. Now plug in x=-6 to solve for y.
y = (-6)² + 12(-6) = 36 - 72 = -36
Therefore vertex is (-6, -36).
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