The age of Blain is 23 years old
<h3><u>Solution:</u></h3>
Let the age of Blain be "a" and age of Jillian be "b"
Given that Blain is two years older than three times Jillians age
So we can frame a equation as:
age of blain = 2 + 3(age of Jillian)
a = 2 + 3b ----- eqn 1
Also given that Jillian is also 16 years younger than Blain
Age of Jillain = Age of Blain - 16
b = a - 16 ---- eqn 2
Substitute eqn 2 in eqn 1
a = 2 + 3(a - 16)
a = 2 + 3a - 48
a - 3a = -46
-2a = -46
a = 23
Thus the age of Blain is 23 years old
It would be $10. There is a formula to this "madness". Divide $97.95 by 9.5%. Ignore the rest of the numbers. (I'm pretty sure it has like 7 or 8, but I only went up to 3. Just make sure you have have the whole number, $10). Hope this helps.
Answer:
2(4x-6)
4(2x-3)
8(x-3/2)
Step-by-step explanation:
find all factors of 8 other than 1, you should have 3
divide the whole equation by the factor then multiply by the factor
2(8x-12)/2 = 2(4x-6)
4(2x-3)
8(x-3/2)
Answer:
1024
Step-by-step explanation:
16x2=32
32x2=64
64x2=128
128x2=256
256x2=512
512x2=1024
x= previous term multiplied by 2
hopefully this helps :)