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3 years ago

Does anyone know these answers??

Mathematics

1 answer:

densk [106]3 years ago

7 0

The angles of a triangle always add up to 180°.

By simply adding the angles and checking the total, you can tell if they make a triangle or not.

Using this property, 5 won't make a triangle, 6 will.

Hope this helps! :D

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Don't know what to do :\\

____ [38]

Answer: Choice A) 12x^2 - 48x + 21; all real numbers

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Work Shown:

(f * g)(x) = f(x) * g(x)
(f * g)(x) = ( f(x) ) * ( g(x) )
(f * g)(x) = ( -2x+7 ) * ( -6x+3 )
(f * g)(x) = -2x*( -6x+3 ) + 7*( -6x+3 )
(f * g)(x) = -2x*(-6x) - 2x*(3) + 7*(-6x) + 7*(3)
(f * g)(x) = 12x^2 - 6x - 42x + 21
(f * g)(x) = 12x^2 - 48x + 21

The domain is the set of all real numbers because we can plug in any number in for x, to get some output for y. There are no issues to worry about such as division by zero errors, square root of a negative number, etc.

6 0

3 years ago

Please help me I don’t know how to do this

OleMash [197]

that is how I solved it

4 0

3 years ago

Read 2 more answers

Evaluate the expression, 7x+8(x-3). Assume that x=4.

NNADVOKAT [17]

Answer:

if x was 4 then the answer would be 36.

Step-by-step explanation:

28+8(4−3)

=28+(8)(1)

=28+8

=36

8 0

3 years ago

A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the

grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = $\frac{diameter}{2}=\frac{66}{2} =33 \ mm$

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = $\frac{4}{3}\pi r^3$

Now Volume of Gumball = $\frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3$

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = $\frac{diameter}{2}=\frac{58}{2} =29 \ mm$

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = $\frac{4}{3}\pi r^3$

So Volume of gumball's spherical hollow core = $\frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3$

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = $150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3$

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = $48347.6\ mm^3$

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0

3 years ago

Find the measure of 44. 41 A2 43 144 970 830 *4 = [?]

Vera_Pavlovna [14]

Angle 4 is 83 degrees

8 0

3 years ago