PLSSS HLEPP ME OUTT ITS URGENTTTT

One of the formulas for calculating the correct dosage for a child is as follows: C= a/((a+12)) ∙ 180 C = child’s dosage in mill

bogdanovich [222]

So you already have the formula for calculating the dosage for child with: C = a/(a+12)x 180 ml Not sure why you have double brackets

variables are: a = child's age, so everywhere you have an "a" replace it with the age of child.

Example: 5 year old child

C = 5/(5+12)*180= 5/(17)*180 = 5/3060 = .0016 ml or milligrams

8 0

3 years ago

Find the area 9cm 8cm 13cm 9cm 11cm

Viktor [21]

Answer:

460

Step-by-step explanation: multiply all numbers to get your answer

6 0

2 years ago

30 points if I had 125 quarter how much money I would have

inna [77]

Answer:

$31.25

Step-by-step explanation:

125 divided by 4 = 31.25

$31.25

4 0

2 years ago

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A TV station claims that 38% of the 6:00 - 7:00 pm viewing audience watches its evening news program. A consumer group believes

Elena L [17]

Answer:

$z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374$

$p_v =P(Z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .

Step-by-step explanation:

1) Data given and notation

n=830 represent the random sample taken

X=282 represent the people that regularly watch the TV station’s news program

$\hat p=\frac{282}{830}=0.340$ estimated proportion of people that regularly watch the TV station’s news program

$p_o=0.38$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.38:

Null hypothesis: $p\geq 0.38$

Alternative hypothesis: $p < 0.38$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .

3 0

2 years ago

Please help. Josh threw darts at a dartboard 10 times. Assume that he threw the darts randomly and did not aim. Based on his res

svp [43]

Here's link to the answer:

tinyurl.com/wtjfavyw

7 0

2 years ago

Read 2 more answers

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PLSSS HLEPP ME OUTT ITS URGENTTTT