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aleksandrvk [35]
2 years ago
14

PLSSS HLEPP ME OUTT ITS URGENTTTT​

Mathematics
1 answer:
8090 [49]2 years ago
6 0
Let the numbers be 7x and 4x
According to question
7x-4x =57
3x =57
X=57/3
X=19
So the numbers are
7x=7*19=133
4x=4*19=76
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Can somone explain to me how to do this and help me thansk!!!
Gnesinka [82]
=> x² = (2.4)² + (4.8)²

=> x² = 5.76 + 23.04

=> x² = 28.8

=> x = 5.366563146

=> x = 5.4

Ans: 2nd option (5.4)

Hope this helps!
6 0
2 years ago
Ava graphs the function h(x) = x2 + 4. Victor graphs the function g(x) = (x + 4)2. Which statements are true regarding the two g
Firlakuza [10]

Answers:

Ava’s graph is a vertical translation of f(x) = x^2.

Ava’s graph moved 4 units from f(x) = x^2 in a positive direction.

Ava’s graph has a y-intercept of 4.

Given:

Ava graphs the function h(x) = x^2 + 4.

Victor graphs the function g(x) = (x + 4)^2

To find y intercept we plug in 0 for x

h(x) = x^2 + 4

h(x) = 0 + 4= 4

So ,Ava’s graph has a y-intercept of 4.

Ava graphs the function h(x) = x^2 + 4

If any number is added at the end then the graph will be shifted up. 4 is added at the end so there will be vertical translation.

Hence , Ava’s graph is a vertical translation of f(x) = x^2. Also Ava moved 4 units up from f(x) = x^2 in a positive y- direction.

Victor graphs the function g(x) = (x + 4)^2

If any number added with x then the graph will be shifted left. the graph will be shifted in negative x direction.


7 0
3 years ago
Read 2 more answers
Simplify the following expression.
o-na [289]

Answer:

i dont know what you mean but

3x(4x-3) simplified is 12x - 4 or 12x+(-4)

3 0
3 years ago
Hem dibuixat tres rectangles. En el primer, la llargada mesura 3 cm més que l'amplada. El segon i tercer rectangle tenen unes di
quester [9]

Resposta:

Primer rectangle:

Amplada = 11

Longitud = 14

Segon rectangle:

Amplada = 12

Longitud = 15

Tercer rectangle:

Amplada = 13

Longitud = 16

Explicació pas a pas:

Donat que:

Primer rectangle:

Amplada = x

Longitud = x + 3

2n rectangle:

Augment de la dimensió d'1 cm respecte al primer rectangle;

Amplada = x + 1

Longitud = x + 4

3r rectangle:

Augment de la dimensió de 2 cm respecte al primer rectangle;

Amplada = x + 2

Longitud = x + 5

Suma dels tres perímetres del rectangle:

Perímetre d'un rectangle: 2 (l + O)

Primer rectangle:

2 (x + x + 3) = 2 (2x + 3) = 4x + 6

2n:

2 (x + 1 + x + 4) = 2 (2x + 5) = 4x + 10

3r:

2 (x + 2 + x + 5) = 2 (2x + 7) = 4x + 14

Suma de perímetres = 162

(4x + 6 + 4x + 10 + 4x + 14) = 162

12x + 30 = 162

12x = 162 - 30

12x = 130

x = 11

Per tant,

Primer rectangle:

Amplada = 11

Longitud = 11 + 3 = 14

2n rectangle:

Amplada = 11 + 1 = 12

Longitud = 11 + 4 = 15

3r rectangle:

Amplada = 11 + 2 = 13

Longitud = 11 + 5 = 16

8 0
3 years ago
If Q is between P and R, then PQ+QR=PR what is the propety
Marina86 [1]

Answer:

Segment Addition Postulate

Step-by-step explanation:

8 0
2 years ago
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