Answer:
The total distance covered is 15.6 miles.
Step-by-step explanation:
One day you warm up for 15 minutes at a pace of 0.1 miles per 25 seconds.
The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. If the relationship between the magnitudes is direct, like in this case, the direct rule of three can be applied as follow:
a ⇒ b
c ⇒ x
Then 
First, the simple rule of three can be applied in the following way: if 1 minute equals 60 seconds, 15 minutes equals how many seconds?

seconds= 900
So now you can apply the following rule of three: if in 25 seconds you travel 0.1 miles, in 900 seconds how many miles do you travel?

distance= 3.6 miles
If you then ride hard for 12 miles, the total distance traveled will be the sum of both:
3.6 miles + 12 miles = 15.6 miles
<u><em>The total distance covered is 15.6 miles.</em></u>
Answer:I think it's trying to find the area of which is a 5 times 2 = 10
Step-by-step explanation:
Anything to a negative power becomes the inverse with the coefficient to a positive power.
For example, 3^-1 becomes 1/3^1 or just 1/3.
3^-2 would be 1/3^2 or 1/9.
Answer:
The mass of the radioactive sample after 40 minutes is 12.8 g.
Step-by-step explanation:
The mass of the sample can be found by using the exponential decay equation:

Where:
N(t): is the amount of the sample at time t =?
N₀: is the initial quantity of the sample = 120 g
t = 40 min
λ: is the decay constant = 0.056 min⁻¹
Hence, the mass of the sample after 40 min is:

Therefore, the mass of the radioactive sample after 40 minutes is 12.8 g.
I hope it helps you!
Answer:
first option
Step-by-step explanation:
Given
f(x) =
← factorise the numerator
=
← cancel (x + 4) on numerator/ denominator
= 2x - 3
Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is
x = - 4
Substitute x = - 4 into the simplified f(x) for y- coordinate
f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11
The discontinuity occurs at (- 4, - 11 )
To obtain the zero let f(x) = 0, that is
2x - 3 = 0 ⇒ 2x = 3 ⇒ x = 
There is a zero at (
, 0 )
Thus
discontinuity at (- 4, - 11 ), zero at (
, 0 )