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2 years ago

9

Write a percent proportion where the part and the whole are known. Solve the problem to find the percent.Show your work, and exp

lain.

1 answer:

valkas [14]2 years ago

6 0

Answer:

what % 65 is 13

Step-by-step explanation:

13/65 = x/100

13 x100

65x = 1,300

You might be interested in

Whats 1,234 in word form

yaroslaw [1]

1,234

One thousand
Two hundred
Thirty four

8 0

3 years ago

Find the area under the standard normal probability distribution between the following pairs of z-scores. a. z=0 and z=3.00 e.

prohojiy [21]

Answer:

a. P(0 < z < 3.00) = 0.4987

b. P(0 < z < 1.00) = 0.3414

c. P(0 < z < 2.00) = 0.4773

d. P(0 < z < 0.79) = 0.2852

e. P(-3.00 < z < 0) = 0.4987

f. P(-1.00 < z < 0) = 0.3414

g. P(-1.58 < z < 0) = 0.4429

h. P(-0.79 < z < 0) = 0.2852

Step-by-step explanation:

Find the area under the standard normal probability distribution between the following pairs of z-scores.

a. z=0 and z=3.00

From the standard normal distribution tables,

P(Z< 0) = 0.5 and P (Z< 3.00) = 0.9987

Thus;

P(0 < z < 3.00) = 0.9987 - 0.5

P(0 < z < 3.00) = 0.4987

b. b. z=0 and z=1.00

From the standard normal distribution tables,

P(Z< 0) = 0.5 and P (Z< 1.00) = 0.8414

Thus;

P(0 < z < 1.00) = 0.8414 - 0.5

P(0 < z < 1.00) = 0.3414

c. z=0 and z=2.00

From the standard normal distribution tables,

P(Z< 0) = 0.5 and P (Z< 2.00) = 0.9773

Thus;

P(0 < z < 2.00) = 0.9773 - 0.5

P(0 < z < 2.00) = 0.4773

d. z=0 and z=0.79

From the standard normal distribution tables,

P(Z< 0) = 0.5 and P (Z< 0.79) = 0.7852

Thus;

P(0 < z < 0.79) = 0.7852- 0.5

P(0 < z < 0.79) = 0.2852

e. z=−3.00 and z=0

From the standard normal distribution tables,

P(Z< -3.00) = 0.0014 and P(Z< 0) = 0.5

Thus;

P(-3.00 < z < 0 ) = 0.5 - 0.0013

P(-3.00 < z < 0) = 0.4987

f. z=−1.00 and z=0

From the standard normal distribution tables,

P(Z< -1.00) = 0.1587 and P(Z< 0) = 0.5

Thus;

P(-1.00 < z < 0 ) = 0.5 - 0.1586

P(-1.00 < z < 0) = 0.3414

g. z=−1.58 and z=0

From the standard normal distribution tables,

P(Z< -1.58) = 0.0571 and P(Z< 0) = 0.5

Thus;

P(-1.58 < z < 0 ) = 0.5 - 0.0571

P(-1.58 < z < 0) = 0.4429

h. z=−0.79 and z=0

From the standard normal distribution tables,

P(Z< -0.79) = 0.2148 and P(Z< 0) = 0.5

Thus;

P(-0.79 < z < 0 ) = 0.5 - 0.2148

P(-0.79 < z < 0) = 0.2852

8 0

3 years ago

What are the coordinates of B

Citrus2011 [14]

Answer:

The coordinates of B is (-5, 4).

7 0

3 years ago

If f(x)=1/9x-2 , what is f–1(x)?

Anna71 [15]

Lets get started :)

f(x) = $\frac{1}{9}x$ - 2
y = $\frac{1}{9}x$ - 2
This is the original equation, and now we have to find the inverse.

When finding the inverse, just flip the variables, x as y and y as x

f ⁻¹(x)
↓
x = $\frac{1}{9}y$ - 2
We have to isolate y as it is our f ⁻¹(x)

Take 2 to the other side { When you see subtraction, you do addition }
x + 2 = $\frac{1}{9} y$

Take 9 to the other side { When you see division, you do multiplication }
9 ( x + 2 ) = y
9x + 18 = y

f ⁻¹ (x) = 9x + 18

7 0

3 years ago

Aleks [24]

Answer:

9+r

Step-by-step explanation:

jessica rode 9 more miles so u would add it to the number of miles roger rode

7 0

3 years ago