Answer:
True
x = 4.32 (2 dp)
Step-by-step explanation:
x³ - 5x = 59
x³ - 5x - 59 = 0
x = 4
4³ - 5(4) - 59 = -15
x = 5
5³ - 5(5) - 59 = +41
A change in sign indicates the existence of root between 4 and 5
Use iterative process to identify the root
x³ - 5x - 59 = 0
x³ = 5x + 59
x = (5x + 59)^⅓
Start at any x between 4 and 5
x(n+1) = (5x(n) + 59)^⅓
x0 = 4.8
x1 = 4.362070671
x2 = 4.323369309
x3 = 4.319915667
x4 = 4.319607202
x5 = 4.318579649
Clearly x is 4.32 (2 dp)
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Answer:</u></h2>
The point M is the midpoint of the line section PQ. Just a line fragment can have a midpoint. A line can't since it goes on uncertainly in the two bearings, thus has no midpoint. A beam can't on the grounds that it has just a single end, and henceforth no midpoint.
The Midpoint Formula works the very same way. In the event that you have to discover the point that is actually somewhere between two given focuses, simply normal the x-values and the y-values.
The answer would be 130.9
Answer:
ans is x=3
Step-by-step explanation: