Attached is my problem
1 answer:
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Answer:
The product of the slopes of lines is -1.
i.e. m₁ × m₂ = -1
Thus, the lines are perpendicular.
Step-by-step explanation:
The slope-intercept form of the line equation
where
- m is the slope
- b is the y-intercept
Given the lines
y = 2/3 x -3 --- Line 1
y = -3/2x +2 --- Line 2
<u>The slope of line 1</u>
y = 2/3 x -3 --- Line 1
By comparing with the slope-intercept form of the line equation
The slope of line 1 is: m₁ = 2/3
<u>The slope of line 2</u>
y = -3/2x +2 --- Line 2
By comparing with the slope-intercept y = mx+b form of the line equation
The slope of line 2 is: m₂ = -3/2
We know that when two lines are perpendicular, the product of their slopes is -1.
Let us check the product of two slopes m₁ and m₂
m₁ × m₂ = (2/3)(-3/2 )
m₁ × m₂ = -1
Thus, the product of the slopes of lines is -1.
i.e. m₁ × m₂ = -1
Thus, the lines are perpendicular.
Answer:
Step-by-step explanation:
You need to complete the square on the right side.
Let x = length of segment EF.
Assume that
(a) line segments AD, EF, and BC are parallel, and
(b) the vertical distance between AD and EF is equal to the vertical distance between EF and BC.
Then from similarity between geometric shapes, we can write
x=3.2 (nearest tenth)
Answer: B. 3.2
Assume that
(a) line segments AD, EF, and BC are parallel, and
(b) the vertical distance between AD and EF is equal to the vertical distance between EF and BC.
Then from similarity between geometric shapes, we can write
x=3.2 (nearest tenth)
Answer: B. 3.2