First, the slope of the line has to be the same for it to be parallel, so the slope(coefficient of x) of the equation is 3.
Next, to make it pass through that specific point, we need to add/subtract a number to make the equation cross that point.
f(x) = 3x at x = 2 evaluates as 6, but the equation needs to pass through the point (2, 3), so we subtract 3 from the equation, leaving us with f(x) = 3x-3.
These triangles are congruent by the hypotenuse-leg theorem, which states that if the hypotenuse and a leg of two right triangles are congruent, the triangles are congruent.
Answer: B) HL
Side note: There is not such thing as AAA congruence. (:
