Answer:
5 cm
Step-by-step explanation:
The distance a coiled spring stretches varies directly with the amount of weight hanging on the spring.
Distance = D
Weight = W
Hence:
D ∝ W
D = kW
Where k is constant of proportionality
Step 1
We solve for k
If a spring stretches 2 cm when a 30 gram weight is hung from it.
2 = 30k
k = 2/30
k = 1/15
Step 2
how far will it stretch when a 75 gram weight is hung from the spring?
We are solving for D
D = 1/15 × 75
D = 5 cm
The spring would stretch 5cm with a weight of 75 gram.
66.66/100
The probability of rolling a dice that lands on 5 is 4/6 (66.667%)
Recent studies show 5 is the most likley number to be rolled on a die
3
Ascending order:
4 ,4 , 4 ,4 ,5, 6 ,7 , 7 ,7
9 data: split in
4 ,4 , 4 ,4 | 5 | 6 ,7 , 7 ,7
4 ,4 | 4 ,4 | 5 | 6 ,7 | 7 ,7
(7+7)/2-(4+4)/2
=7-4
=3
