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3 years ago

Find the length of CA to the nearest tenth of a foot

Mathematics

1 answer:

hoa [83]3 years ago

3 0

Answer:

CA ≈ 3.1 ft

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan40° = $\frac{opposite}{adjacent}$ = $\frac{BC}{CA}$ = $\frac{2.6}{CA}$ ( multiply both sides by CA )

CA × tan40° = 2.6 ( divide both sides by tan40° )

CA = $\frac{2.6}{tan40}$ ≈ 3.1 ft ( to the nearest tenth )

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Find the substance's half-life, in days.<br> Round your answer to the nearest tenth.

shutvik [7]

Answer:

t = 5.6 day

t =5 days 14 hours 24 minutes

Step-by-step explanation:

Half life is the time it will take for the original value or quantity I'd a particular substance to decrease by half of it's original self.

N = N•e(-kt)

N• = 25

K = 0.1229

Then

N = 25/2 = 12.5

The reason because at the half life , it's original value will decrease to half.

Let's solve for the half life t

N = N•e(-kt)

12.5 = 25e(-0.1229t)

12.5/25 = e(-0.1229t)

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4 years ago

What is the y-value when x equals - 12?

kirill115 [55]

Answer:

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3 years ago

Find the maximum and the minimum value of the following objective function, and the value of x and y at which they occur. The f

kumpel [21]

Answer:

The maximum value of the objective function is 112 when x = 0 and y = 7.

Step-by-step explanation:

Given the constraints:

5x+3y≤37, 3x+5y≤35, x≥0, y≥0

Plotting the above constraints using geogebra online graphing tool, we get the solution to the constraints as:

A(0, 7), B(7.4, 0), C(5, 4) and D(0, 0)

The objective function is given as E =2x+16y, therefore:

At point A(0, 7): E = 2(0) + 16(7) = 112

At point B(7.4, 0): E = 2(7.4) + 16(0) = 14.8

At point C(5, 4): E = 2(5) + 16(4) = 74

At point D(0, 0): E = 2(0) + 16(0) = 0

Therefore the maximum value of the objective function is at A(0, 7).

The maximum value of the objective function is 112 when x = 0 and y = 7.

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