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KonstantinChe [14]
2 years ago
11

Find the length of CA to the nearest tenth of a foot

Mathematics
1 answer:
hoa [83]2 years ago
3 0

Answer:

CA ≈ 3.1 ft

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan40° = \frac{opposite}{adjacent} = \frac{BC}{CA} = \frac{2.6}{CA} ( multiply both sides by CA )

CA × tan40° = 2.6 ( divide both sides by tan40° )

CA = \frac{2.6}{tan40} ≈ 3.1 ft ( to the nearest tenth )

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a) starting height: 5.5 ft

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b) The ball is in the air between t=0 and the non-zero time when h(t) = 0. We can find the latter by solving ...

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The maximum height will be reached at t = 2.75 seconds.

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