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4 years ago

What are prime numbers?

1 answer:

5 0

Prime numbers are number that can't be divided except it is it's self and 1. For example, 3,5,7,11,13,17, 19, 23, 29, 31, 37...... All of those numbers can only be divided with itself and 1.

3 = 3x1
7 = 7x1
23= 23 x 1

hope this helps

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Use the fact that 135 X 37= 4,995 to find the value of 1,350 X 3,700?

Dimas [21]

Answer:

The anwser is 4,995,000 ok

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3 years ago

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pickupchik [31]

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3 years ago

Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (

kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

$f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2})$ is given as continuous function, so there exist $lim_{(x,y)\rightarrow(0,0)}f(x,y)$ and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

$f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})$

we know that $cos^2A+sin^2A=1$ , so we have that

$f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)$

$lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19$

So f(0,0)=ln19.

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3 years ago

What is teh units form 0.12

tia_tia [17]

Answer:

I think 5/60.......

u welcome

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3 years ago

Read 2 more answers

HELP ME WITH THIS QUESTION PLEASE

lara [203]

Answer:

0.79

Step-by-step explanation:

all you really need to do is multiply your decimal (15.8) by your percent (5) so, you problem would look like 15.8(.05) (note it is .<em>0</em>5 because there need to be 2 decimal places) so, your answer is .79

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3 years ago