Answer:
Solution 2. A right triangle is formed with the bottom of the flagpole, the snapped part, and the ground. One leg is of length $1 ...
Missing: picture way barely
Step-by-step explanation:
A flagpole is originally $5$ meters tall. A hurricane snaps the flagpole at a point $x$ meters above the ground so that the upper part, still attached to the stump, touches the ground $1$ meter away from the base. What is $x$?
$\text{(A) } 2.0 \qquad \text{(B) } 2.1 \qquad \text{(C) } 2.2 \qquad \text{(D) } 2.4 \qquad \text{(E) } 2.5$
Solution 1
The broken flagpole forms a right triangle with legs $1$ and $x$, and hypotenuse $5-x$. The Pythagorean theorem now states that $1^2 + x^2 = (5-x)^2$, hence $10x = 24$, and $x=\boxed{2.4}$.
(Note that the resulting triangle is the well-known $5-12-13$ right triangle, scaled by $1/5$.)
Solution 2
A right triangle is formed with the bottom of the flagpole, the snapped part, and the g
Answer:
Step-by-step explanation:
The formula for determining the length of a rectangle is expressed as
Area = length × width
The large rectangle has a length of 10 units and width 5 units. The area of the large rectangle would be
10 × 5 = 50 units²
Inside this rectangle is a smaller rectangle of length 4 units and width 2 units. The area of the smaller rectangle would be
4 × 2 = 8 units²
Probability is expressed as favorable outcome/total number of possible outcomes
The region that is not shaded grey is
50 - 8 = 42 units²
The probability that a point chosen inside the large rectangle is not in the shaded region is
42/50 = 0.84
Converting to percentage, it becomes
0.84 × 100 = 84%
ANSWER

EXPLANATION
The given vector is v = −14.5i + 2.5 j.
The magnitude of this vector is



The unit vector in the direction of this vector is



Answer:
Step-by-step explanation:
Your line has the wrong slope. Its slope is ½, but the equation tells you that the slope is ¾.
The point (0,2) is correct, but (-4,0) is incorrect. If x=-4 then y=-1, not 0.
Plot (-4,-1), then draw the line passing through (-4,-1) and (0,2).
8:41 a.m.
Thirty-five minutes after 8:06 a.m. means
8:06
0:35 +
_____
8:41 a.m.