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3 years ago

Is (2, 5) a solution to this system of equations? y = x + 3 y = 7x + 6

Mathematics

1 answer:

vfiekz [6]3 years ago

7 0

Answer:

No is not the solution to that system

Step-by-step explanation:

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My brother is currently three times as old as me, but in five years, my brother

wolverine [178]

Answer: Your brother is 15 years old right now.

Step-by-step explanation:

Let be "m" your currently age and "b" your brother's currently age.

Knowing that right now he is three times (this indicates multiplication) as old as you, you can write the following equation:

$b=3m$

In five years your age will be:

$m+5$

And your brother's age will be:

$b+5$

Then, if in five years, your brother will be twice as old as you, you can set up the second equation:

$b+5=2(m+5)$

Then, the System of equations is:

$\left \{ {{b=3m} \atop {b+5=2(m+5)}} \right.$

Apply the Substitution method and substitute the first equation into the second one and solve for "m":

$3m+5=2(m+5)\\\\3m+5=2m+10\\\\m=10-5\\\\m=5$

Substitute the value of "m" into the first equation and evaluate in order to find "b":

$b=3(5)\\\\b=15$

4 0

3 years ago

Consider the two functions given below.

mestny [16]

This means which transformation makes the same answer at x = 0

f(x) = 3x + 4
$g(x) = {2}^{x} - 1$

f(0) = 4
g(0) = 1 - 1 = 0

Which transformation makes 4 = 0?

4 + x = 0 + y

4 - 3 =0 + 1

1 = 1

Option 1 is your answer

3 0

3 years ago

Read 2 more answers

(2 4/10 + 8 4/5) - 3 1/5

True [87]

Answer:

it says use a calculater maybe if u used one it would help u out.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Complete the table for each function. Then

Aleks04 [339]

A=ba ca
E= ce de
I don’t know

6 0

2 years ago

Which of the following expressions can be used to complete the equation below Secx / 1+cot^2x=

svlad2 [7]

Answer: D) Tan x sin x

<u>Step-by-step explanation:</u>

$\dfrac{sec}{1+cot^2}\\\\\\=\dfrac{1}{cos}\cdot \dfrac{1}{1+cot^2}\\\\\\=\dfrac{1}{cos}\cdot \dfrac{1}{1+(\frac{cos}{sin})^2}\\\\\\=\dfrac{1}{cos}\cdot \dfrac{1}{(\frac{sin^2}{sin^2})+(\frac{cos^2}{sin^2})}\\\\\\=\dfrac{1}{cos}\cdot \dfrac{sin^2}{sin^2+cos^2}\\\\\\=\dfrac{1}{cos}\cdot \dfrac{sin^2}{1}\\\\\\=\dfrac{sin\cdot sin}{cos\cdot 1}\\\\\\=\boxed{tan\cdot sin}$

3 0

3 years ago