Answer:
A
Step-by-step explanation:
![cos~ \theta=\sqrt{1-sin^2 \theta} =\sqrt{1-(\frac{1}{2})^2 } =\frac{\sqrt{3} }{2} \\1+cos~\theta=2cos^2\frac{\theta}{2} \\1+\frac{\sqrt{3}}{2} =2~cos^2 \frac{\theta}{2} \\cos^2\frac{\theta}{2} =\frac{2+\sqrt{3}}{2 \times 2} \\cos \frac{\theta}{2} =\frac{\sqrt{2+\sqrt{3}}}{2} \\1-cos \theta=2 ~sin^2\frac{\theta}{2} \\1-\frac{\sqrt{3}}{2}=2~sin^2 \frac{\theta}{2} \\sin^2 \frac{\theta}{2} =\frac{2-\sqrt{3} }{2 \times 2} \\sin \frac{\theta}{2}=\frac{\sqrt{2-\sqrt{3} } }{2}](https://tex.z-dn.net/?f=cos~%20%5Ctheta%3D%5Csqrt%7B1-sin%5E2%20%5Ctheta%7D%20%3D%5Csqrt%7B1-%28%5Cfrac%7B1%7D%7B2%7D%29%5E2%20%7D%20%3D%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B2%7D%20%5C%5C1%2Bcos~%5Ctheta%3D2cos%5E2%5Cfrac%7B%5Ctheta%7D%7B2%7D%20%5C%5C1%2B%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%20%3D2~cos%5E2%20%5Cfrac%7B%5Ctheta%7D%7B2%7D%20%5C%5Ccos%5E2%5Cfrac%7B%5Ctheta%7D%7B2%7D%20%3D%5Cfrac%7B2%2B%5Csqrt%7B3%7D%7D%7B2%20%5Ctimes%202%7D%20%5C%5Ccos%20%5Cfrac%7B%5Ctheta%7D%7B2%7D%20%3D%5Cfrac%7B%5Csqrt%7B2%2B%5Csqrt%7B3%7D%7D%7D%7B2%7D%20%5C%5C1-cos%20%5Ctheta%3D2%20~sin%5E2%5Cfrac%7B%5Ctheta%7D%7B2%7D%20%5C%5C1-%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%3D2~sin%5E2%20%5Cfrac%7B%5Ctheta%7D%7B2%7D%20%5C%5Csin%5E2%20%5Cfrac%7B%5Ctheta%7D%7B2%7D%20%3D%5Cfrac%7B2-%5Csqrt%7B3%7D%20%7D%7B2%20%5Ctimes%202%7D%20%5C%5Csin%20%5Cfrac%7B%5Ctheta%7D%7B2%7D%3D%5Cfrac%7B%5Csqrt%7B2-%5Csqrt%7B3%7D%20%7D%20%7D%7B2%7D)
as 0≤θ≤90
so θ/2 is also in 0≤θ≤90
hence sin θ/2 and cos θ/2 are positive.
Answer:
there are dots outside of the allotted area
Step-by-step explanation:
I've never taken a math help class but from your paper one can assume you have to point out the error in the graph. Its a bit fuzzy so I cant see the numbers or labels but you take what you learned for how to graph and apply it here.
For example:
The dots should stay inside the graph. Not on the outside
The numbers that are on the side, the axis, they should all progress in a specific sequence. Like 2,4,6,8,10. It needs to stay constant. Not 2,4,6,8,19
Same for both x and y axis^
I'm not sure if that helps much with what your doing seeing as the instructions apply what you've already learned, but I hope you do good!
First find the volume of the cylinder, then the volume of the cone, and after you can add the two volumes.
Cylinder:
V = π r^2 h
h = 12 inches
r = 4 inches
V = π(4^2)(12)
V = 192π
Cone:
V = 1/3 π r^2 h
h = 6 inches
r = 4 inches
V = 1/3 π (4^2)(6)
V = 32π
Now adding the two volumes, 192π + 32π = 224π cubic inches
Answer:
5 hot dogs packs at least and 4 buns packs at least
Step-by-step explanation: