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Ostrovityanka [42]
2 years ago
5

What is the interquartile range (IQR) of this data set?

Mathematics
2 answers:
Andreas93 [3]2 years ago
7 0

Answer:

11 is the median of the entire data set

6 is the median of the lower half and 16 is the median of the upper half data scores...

Subtract 16 from 6 gives 10 so the answer is C) 10

Sever21 [200]2 years ago
6 0
<h3>Answer:  Choice C)  10</h3>

=============================================================

Explanation:

The first step is to sort the data from smallest to largest. Luckily, that's already been done for us.

Next, we find the median. This is the middle most number of the set. In this case, the median is 11 since we have 3 values below it (2,6,7) and 3 values above it (15,16,17).

Let

L = {2,6,7}

U = {15,16,17}

where L and U are the lower and upper sets respectively.

In other words, anything in set L is lower than the median while anything in set U is above the median. The median itself (11) is not part of either set.

Notice how 6 is the midpoint of set L, while 16 is the midpoint of set U.

This means Q1 = 6 and Q3 = 16

Therefore,

IQR = Q3 - Q1

IQR = 16 - 6

IQR = 10

which is why choice C is the final answer.

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Need help with this math
serg [7]

we use the interest formula. 4000*1.03^11=1.38423387*4000=5536.93548, or 5536.94.

5 0
3 years ago
Help w this pls it would save me<br> Pleasereeee
elena55 [62]

Answer:

0.6 over 0.6. Or just 1.

Step-by-step explanation:

5 0
2 years ago
Find the probability.
KATRIN_1 [288]

Using it's concept, it is found that there is a 0.0366 = 3.66% probability that your coach and your friend get orange and you get a fruit-punch.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem, there are 15 bottles.

  • 5 are orange, hence the is a 5/15 = 1/3 probability that the coach gets orange, hence P(A) = 1/3.
  • After the coach, there will be 14 bottles remaining, of which 4 are orange, hence the probability that the friend gets orange is of P(B) = 4/14 = 2/7.
  • For you, there will be 13 bottles remaining, of which 5 will be of fruit-punch, hence the probability you get fruit-punch is of P(C) = 5/13.

The probability of the three outcomes occurring is given by:

p = \frac{1}{3} \times \frac{2}{7} \frac{5}{13} = \frac{10}{273} = 0.0366

0.0366 = 3.66% probability that your coach and your friend get orange and you get a fruit-punch.

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

6 0
2 years ago
A boat that costs $8550 decreases in value by 12% per year. How much will the boat be worth after 3 years?
erastovalidia [21]
You have to take $8,550 times 0.12 (12%) to find out the number it is being decreased by.
8,550 x 0.12 = 1,026
And then, you have to subtract 1,026 from 8,550 three times for three years and your answer becomes 5,472.
$5,472
3 0
3 years ago
Regina brought 8 7/8 pound of fruit for her family . She brought 3 1/2 pound of oranges and 2 3/4 pound of peaches and some appl
butalik [34]

Answer:

Regina has bought 2\frac{5}{8}\ pounds of apples.

Step-by-step explanation:

Given:

Amount of fruit brought = 8\frac{7}{8}\ pounds

Now given number is in mixed fraction we will convert into improper fraction.

To convert a mixed fraction to an improper fraction, we will Multiply the whole number part by the fraction's denominator.  Add that to the numerator,Then write the result on top of the denominator.

So we can say that;

8\frac{7}{8}\ pounds can be Rewritten as \frac{71}{8}\ pounds

Amount of fruit brought = \frac{71}{8}\ pounds

Also given:

Amount of oranges bought = 3\frac12\ pounds

3\frac12\ pounds can be Rewritten as \frac{7}{2}\ pounds

Amount of oranges bought =  \frac{7}{2}\ pounds

Amount of peaches bought = 2 \frac34\ pounds

2 \frac34\ pounds can be Rewritten as \frac{11}{4}\ pounds

Amount of peaches bought =  \frac{11}{4}\ pounds

We need to find amount of apples bought by Regina.

Solution:

Let the amount of apples bought be 'x'

Now we know that;

Amount of fruit brought is equal to sum of Amount of oranges bought and Amount of peaches bought amount of apples.

framing in equation form we get;

\frac{71}{8}=\frac{7}{2}+\frac{11}{4}+x\\\\x=\frac{71}{8}-\frac{7}{2}-\frac{11}{4}

Now we will make the denominator common using LCM we get.

x=\frac{71\times 1}{8\times 1}-\frac{7\times4}{2\times4}-\frac{11\times2}{4\times2}\\\\x=\frac{71}{8}-\frac{28}{8}-\frac{22}{8}

Now denominators are same so we will solve the numerator.

x=\frac{71-28-22}{8}\\\\x=\frac{21}{8}\ pounds

Now \frac{21}{8}\ pounds can be Rewritten as 2\frac{5}{8}\ pounds

Hence Regina has bought 2\frac{5}{8}\ pounds of apples.

5 0
3 years ago
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