Ask question

Ask question

All categories

2 years ago

10

Write Tic tac toe program in python for beginners pls

Computers and Technology

1 answer:

Travka [436]2 years ago

4 0

Answer:

#Implementation of Two Player Tic-Tac-Toe game in Python.

''' We will make the board using dictionary

in which keys will be the location(i.e : top-left,mid-right,etc.)

and initialliy it's values will be empty space and then after every move

we will change the value according to player's choice of move. '''

theBoard = {'7': ' ' , '8': ' ' , '9': ' ' ,

'4': ' ' , '5': ' ' , '6': ' ' ,

'1': ' ' , '2': ' ' , '3': ' ' }

board_keys = []

for key in theBoard:

board_keys.append(key)

''' We will have to print the updated board after every move in the game and

thus we will make a function in which we'll define the printBoard function

so that we can easily print the board everytime by calling this function. '''

def printBoard(board):

print(board['7'] + '|' + board['8'] + '|' + board['9'])

print('-+-+-')

print(board['4'] + '|' + board['5'] + '|' + board['6'])

print('-+-+-')

print(board['1'] + '|' + board['2'] + '|' + board['3'])

# Now we'll write the main function which has all the gameplay functionality.

def game():

turn = 'X'

count = 0

for i in range(10):

printBoard(theBoard)

print("It's your turn," + turn + ".Move to which place?")

move = input()

if theBoard[move] == ' ':

theBoard[move] = turn

count += 1

else:

print("That place is already filled.\nMove to which place?")

continue

# Now we will check if player X or O has won,for every move after 5 moves.

if count >= 5:

if theBoard['7'] == theBoard['8'] == theBoard['9'] != ' ': # across the top

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

elif theBoard['4'] == theBoard['5'] == theBoard['6'] != ' ': # across the middle

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

elif theBoard['1'] == theBoard['2'] == theBoard['3'] != ' ': # across the bottom

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

elif theBoard['1'] == theBoard['4'] == theBoard['7'] != ' ': # down the left side

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

elif theBoard['2'] == theBoard['5'] == theBoard['8'] != ' ': # down the middle

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

elif theBoard['3'] == theBoard['6'] == theBoard['9'] != ' ': # down the right side

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

elif theBoard['7'] == theBoard['5'] == theBoard['3'] != ' ': # diagonal

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

elif theBoard['1'] == theBoard['5'] == theBoard['9'] != ' ': # diagonal

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

# If neither X nor O wins and the board is full, we'll declare the result as 'tie'.

if count == 9:

print("\nGame Over.\n")

print("It's a Tie!!")

# Now we have to change the player after every move.

if turn =='X':

turn = 'O'

else:

turn = 'X'

# Now we will ask if player wants to restart the game or not.

restart = input("Do want to play Again?(y/n)")

if restart == "y" or restart == "Y":

for key in board_keys:

theBoard[key] = " "

game()

if __name__ == "__main__":

game()

<em>HOPE THIS HELPS :)</em>

You might be interested in

Why is it important to verify a customer complaint?

diamong [38]

B.Proper diagnosis will save time and money

8 0

2 years ago

The names of the governing body or organizationds that creates rules for information technology and information communication te

IceJOKER [234]

Answer:

Alliance for Telecommunications Industry Solutions

Explanation:

Alliance for Telecommunications Industry Solutions is the main body that creates rules for information technology and information communication technology.

This agency create solutions to supports the release of new products and services into the communications marketplace. It also act as an agency that standardizes the wireless and wireline networks activities. It is accredited by the American National Standards Institute (ANSI).

5 0

2 years ago

The operating system (OS) of an information system contains the software that executes the critical functions of the information

Feliz [49]

Answer:

a. True

Explanation:

An information system (IS) can be defined as a set of components or computer systems, which is used to collect, store, and process data, as well as dissemination of information, knowledge, and distribution of digital products.

Generally, it is an integral part of human life because individuals, organizations, and institutions rely on information systems in order to perform their duties, functions or tasks and to manage their operations effectively. For example, all organizations make use of information systems for supply chain management, process financial accounts, manage their workforce, and as a marketing channels to reach their customers or potential customers.

Additionally, an information system comprises of five (5) main components;

1. Hardware.

2. Software.

3. Database.

4. Human resources.

5. Telecommunications.

An operating system is a system software pre-installed on a computing device to manage or control software application, computer hardware and user processes.

This ultimately implies that, an operating system acts as an interface or intermediary between the computer end user and the hardware portion of the computer system (computer hardware) in the processing and execution of instructions.

On a related note, the software application that executes the critical functions of an information system (IS) are contained in its operating system (OS).

Basically, the computer's memory, processes, softwares and hardwares are typically being managed by the operating system (OS). Thus, an OS makes it possible for different programs to run simultaneously (more than one software program running concurrently) and access the computer's memory, central processing unit (CPU), and storage.

4 0

2 years ago

Which of the following is true of the 529 plan

sesenic [268]

A 529 Plan is an education savings plan operated by a state or educational institution designed to help families set aside funds for future college costs.

your answer will be: It is a tax-advantaged college savings plan.

5 0

2 years ago

Read 2 more answers

Suppose you have two arrays of ints, arr1 and arr2, each containing ints that are sorted in ascending order. Write a static meth

telo118 [61]

Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.

public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}

So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.

A quick explanation:

We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.

The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.

4 0

3 years ago