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3 years ago

10

Write Tic tac toe program in python for beginners pls

Computers and Technology

1 answer:

Travka [436]3 years ago

4 0

Answer:

#Implementation of Two Player Tic-Tac-Toe game in Python.

''' We will make the board using dictionary

in which keys will be the location(i.e : top-left,mid-right,etc.)

and initialliy it's values will be empty space and then after every move

we will change the value according to player's choice of move. '''

theBoard = {'7': ' ' , '8': ' ' , '9': ' ' ,

'4': ' ' , '5': ' ' , '6': ' ' ,

'1': ' ' , '2': ' ' , '3': ' ' }

board_keys = []

for key in theBoard:

board_keys.append(key)

''' We will have to print the updated board after every move in the game and

thus we will make a function in which we'll define the printBoard function

so that we can easily print the board everytime by calling this function. '''

def printBoard(board):

print(board['7'] + '|' + board['8'] + '|' + board['9'])

print('-+-+-')

print(board['4'] + '|' + board['5'] + '|' + board['6'])

print('-+-+-')

print(board['1'] + '|' + board['2'] + '|' + board['3'])

# Now we'll write the main function which has all the gameplay functionality.

def game():

turn = 'X'

count = 0

for i in range(10):

printBoard(theBoard)

print("It's your turn," + turn + ".Move to which place?")

move = input()

if theBoard[move] == ' ':

theBoard[move] = turn

count += 1

else:

print("That place is already filled.\nMove to which place?")

continue

# Now we will check if player X or O has won,for every move after 5 moves.

if count >= 5:

if theBoard['7'] == theBoard['8'] == theBoard['9'] != ' ': # across the top

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

elif theBoard['4'] == theBoard['5'] == theBoard['6'] != ' ': # across the middle

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

elif theBoard['1'] == theBoard['2'] == theBoard['3'] != ' ': # across the bottom

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

elif theBoard['1'] == theBoard['4'] == theBoard['7'] != ' ': # down the left side

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

elif theBoard['2'] == theBoard['5'] == theBoard['8'] != ' ': # down the middle

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

elif theBoard['3'] == theBoard['6'] == theBoard['9'] != ' ': # down the right side

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

elif theBoard['7'] == theBoard['5'] == theBoard['3'] != ' ': # diagonal

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

elif theBoard['1'] == theBoard['5'] == theBoard['9'] != ' ': # diagonal

printBoard(theBoard)

print("\nGame Over.\n")

print(" **** " +turn + " won. ****")

break

# If neither X nor O wins and the board is full, we'll declare the result as 'tie'.

if count == 9:

print("\nGame Over.\n")

print("It's a Tie!!")

# Now we have to change the player after every move.

if turn =='X':

turn = 'O'

else:

turn = 'X'

# Now we will ask if player wants to restart the game or not.

restart = input("Do want to play Again?(y/n)")

if restart == "y" or restart == "Y":

for key in board_keys:

theBoard[key] = " "

game()

if __name__ == "__main__":

game()

<em>HOPE THIS HELPS :)</em>

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