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Anastaziya [24]
3 years ago
13

Amy, Bodie, Claire, and Dejan are in the same math class. The locations of their desks in relation to each other are graphed on

the coordinate plane below.
If the length of each square represents one foot, how far is it from Claire's desk to Dejan's desk?
A.
9 feet
B.
8 feet
C.
7 feet
D.
10 feet ?
Mathematics
1 answer:
Xelga [282]3 years ago
5 0

Answer:10 ft

Step-by-step explanation:

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1, 1/4, 1/9, 1/16, 1/25.... write the explicit formula for this sequence
Dimas [21]

a_n=\dfrac{1}{n^2}

8 0
3 years ago
Read 2 more answers
Sum of first n terms of an ap sequance is 3n2+5n.what is the sum of its first n+1 terms.find the sum of its first 10 terms.
inessss [21]

Answer:

a) 3n^2 + 11n + 8

b) 350

Step-by-step explanation:

10) 3(10^2)+ 5*10 = 350

n+1) 3(n+1)^2 + 5(n+1)

        3(n^2 + 2n + 1) + 5n+5

         3n^2 + 6n+3 + 5n + 5

           3n^2 + 11n + 8

3 0
3 years ago
What is the height of a right triangle if its other two sides are 30 centimeters and 10 centimeters long?​
Mila [183]

Answer:

Step-by-step explanation:

It depends on whether the 30 cm side is the hypotenuse, or one of the legs.

If the 30 cm side is the hypotenuse, then the third side is √(30^2-10^2) = √800 = 20√2 cm

If the 30 cm side is one of the legs, then the hypotenuse is √(30^2+10^2) = √1,000 = 10√10 cm

7 0
3 years ago
Please help! Help me with the steps as well not just answers:/
serious [3.7K]
For question 1 you need to find the sqared values of the hypotenuse, which has a length of 15, and leg b, which has a length of 12. This gives you a hypotenuse of 225 and a leg which is 144. Subtract your given leg squared from your hypotenuse squared (aka 225-144). This leaves you with 81. Now find the square root of this, which is 9.

For question 2 you need to find the squared value of legs a and b. Leg a has an initial length of 6, which squared is 36. The same applies for leg b. Now add 36 to 36 to get 72. All you have to do is find the square root of that to have your answer. Since 72 isn't a perfect square, just simplify the root to 3 root 8, aka
3 \sqrt{8}
For question 3, repeat the process used in question 1. The square of a square root is the original number (ex: the sqare root of 3 squared is 3). Subtract 7 from 19 to get 12. 12 isn't a perfect square, so simplify the root. You should end up with 2 root 3, aka
2 \sqrt{3}

For question 4 you must find the sqared value of a, b, and c. The sum of the sqared values of a and b is equal to the squared value of c. If c is 10 and a and b are both x, then the formula is
{x}^{2} +  {x}^{2} = 100
or
2 {x}^{2} = 100
Next, simplify this by first dividing by 2 on each side. You are then left with x squared equals 50. Simplify the root to 5 root 2, aka
5 \sqrt{2}

For question 5 you need to find the squared value of 47 and 25. This leaves you a hypotenuse of 2209 and a width of 625. Subtract 625 from 2209. This leaves you with 1584. Find the sqare root of this to find your length. Since it isn't a perfect square, simplify the root to get 12 root 11, aka
12 \sqrt{11}

I hope this helps clear things up for you!
3 0
3 years ago
Given 5x/11 2. choose the solution set
Vanyuwa [196]
Same!!! The answer is {x | x < 22/5}, and don't ask me to explain it because I cant.
8 0
3 years ago
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