The answer is 5,000!!!!!!!!!!!!!!!!!!!!!!!
Answer:
ideas and conflict and maybe elements depending on the story
The answer is three < five
We take the equation
<span>x^2 -4x + y^2 + 6y + 12 = 0
and complete the square for x and y.
</span><span>x^2 -4x + 4 - 4 + y^2 + 6y + 9 - 9 + 12= 0</span>
<span> (x-2)^2 - 4 + (y+3)^2 - 9 = -12</span>
<span> <span>(x-2)^2+ (y+3)^2 = 1
Therefore the answer is </span></span><span>(x-2)^2+ (y+3)^2 = 1</span>
The correct question is
<span>The product of two consecutive positive integers is
11 more than their sum. find the integers.
Let
x-------> the first </span>positive integer
x+1-----> the second consecutive positive integer
we know that
x*(x+1)=11+(x+(x+1))----> x²+x=11+(2x+1)----> x²+x=2x+12
x²-x-12=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solution is
x=4
therefore
the numbers are
x=4
x+1=5
the answer isthe numbers are 4 and 5