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vlada-n [284]
3 years ago
15

Determine the product of the following expressions

Mathematics
1 answer:
Elanso [62]3 years ago
6 0

Answer:

1. x^3+27y^3

2. 10a^3+17a^2b+11ab^2+12b^3

Step-by-step explanation:

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Using the digits 0 to 9, without repetition, fill the blanks.
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First angle to the right inside the triangle can be 60
Other angle inside the triangle can be 40
The upper angle outside the triangle 80
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Solve for p. 7(p-9) = -34. 3
dedylja [7]

Answer:

p=4.1

Step-by-step explanation:

6 0
3 years ago
What is the equation of a line , in a slope -intercept form , that passes through (5,-3) and has a slope of 2/3? A. y-3= 2/3(x+5
zmey [24]
Ur asking for slope intercept form, but ur answer choices are in point slope form....so I am gonna find the answer in point slope form.

y - y1 = m(x - x1)
slope(m) = 2/3
(5,-3)....x1 = 5 and y1 = -3
now we sub...but pay very close attention to ur signs
y - (-3) = 2/3(x - 5) = 
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8 0
4 years ago
Please help! ( WIll mark Brianliest ) <br><br> Help
sashaice [31]

Answer:y= (3/4)x -7/4

Step-by-step explanation:

[y -(-1)]/[x - 1] = [2 -(-1)]/[5 - 1]

[y + 1]/[x - 1] = 3/4

y + 1 = (3/4)x - 3/4

y = (3/4)x - 7/4.

6 0
3 years ago
pls solve quickly!: It took a boat 2 hours to reach town A going upstream. The way back was 1h20 min. What is the speed of the b
goldenfox [79]

Answer:

15 mph

Step-by-step explanation:

Given: Boat took 2 hours to reach Town A going upstream.

           Speed of stream= 3 mph

           Time taken to reach back home= 1 hours 20 minutes

Lets assume distance covered one side be "d" and speed of boat in still water be "s".

∴ Speed of boat in upstream= (s-3) \ mph

   Speed of boat in downstream= (s+3)\ mph

Also converting into fraction of time taken to reach back home.

Remember; 1 hour= 60 minutes

∴ Time taken to reach back home= 60+20= 80\ minutes

Converting time given into fraction= \frac{80\ minutes}{60\ minutes} = \frac{4}{3} \ hours

hence, Time taken to reach back home is \frac{4}{3} \ hours

Now forming equation of boat travelling upstream and downstream, considering distance remain constant.

We know, Distance= speed \times  time

⇒ (s-3)\times 2= (s+3)\times \frac{4}{3}

Using distributive property of multiplication

⇒2s-6= \frac{4}{3}s +4

subtracting both side by \frac{4}{3} s

⇒2s-\frac{4}{3} s-6= 4

Adding both side by 6

⇒ 2s-\frac{4}{3} s= 10

taking LCD as 3

⇒ \frac{2}{3} s= 10

Multiplying both side by \frac{3}{2}

⇒s= \frac{3}{2} \times 10

∴s= 15 mph

Hence, 15 mph is the speed of the boat in still water.

8 0
4 years ago
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