First, we have to find how many times 10 goes into 15.

We can divide 15 by 10, and we will see that 10 goes into 15 1 whole time, with 5/10 left over.

Now, we can simplify!

In order to simplify, we have to find the GCF (greatest common factor) of 5 and 10. Let's list out the factors (the numbers that can be divided into 5 and 10)

1*5

1*10
2*5

The largest factor, as we can see, is 5! Let's dicide 5/10 by 5.

5/5=1
10/5=2

So, 5/10 simplifies to 1/2, and, if we bring down the whole number we found before, 15/10 is equal to 1 and 1/2! :)

We can check this answer by multiplying the whole number, 1, by the denominator, (the bottom number of a fraction) 2, and adding the numerator, (the top number of a fraction), 1.

1*2=2
2+1=3

Keep the denominator as 2.

The improper fraction is 3/2, which is equivalent to 15/10 (multiply 3/2 by 5 to see)!

So, our answer is 1 1/2.

I hope I helped! :)

3 0

3 years ago

What is the value of the fourth term in a geometric sequence for which a1 = 30 and r = 1/2?

Pani-rosa [81]

Answer: The required fourth term of the geometric sequence is $\dfrac{10}{9}.$

Step-by-step explanation: We are given to find the value of the fourth term in a geometric sequence with first term and common ratio as follows :

$a(1)=30,~~~~~r=\dfrac{1}{2}.$

We know that

the n-th term of a geometric sequence with first term a1 and common ratio r given by

$a(n)=a(1)r^{n-1}.$

Therefore, the fourth term of the given geometric sequence will be

$a(4)=a(1)r^{4-1}=30\times r^3=30\times\left(\dfrac{1}{3}\right)^3=\dfrac{30}{27}=\dfrac{10}{9}.$

Thus, the required fourth term of the geometric sequence is $\dfrac{10}{9}.$

7 0

2 years ago

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