Question

102 - Harder brackets

Answer 1

Answer:

For figure 1:

Area of rectangle = 7x + 21

For figure 2:

Area of rectangle = $\mathbf{p^2-9p }$

Step-by-step explanation:

We need to find area of rectangle

The formula used is: $Area\:of\:rectangle=Length\times Width$

For figure 1:

Length = 7

Width = x+3

Putting values in formula and finding area of rectangle

$Area\:of\:rectangle=Length\times Width\\Area\:of\:rectangle=7\times (x+3)\\Now,\: multiply\:7\:with\:terms\;inside\:the\:bracket\\Area\:of\:rectangle=7(x)+7(3)\\Area\:of\:rectangle=7x+21$

So, area of rectangle = 7x + 21

For figure 2:

Length = p

Width = p-9

Putting values in formula and finding area of rectangle

$Area\:of\:rectangle=Length\times Width\\Area\:of\:rectangle=p\times (p-9)\\Now,\: multiply\:p\:with\:terms\;inside\:the\:bracket\\Area\:of\:rectangle=p(p)-p(9)\\Area\:of\:rectangle=p^2-9p$

So, area of rectangle = $\mathbf{p^2-9p }$