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3 years ago

The wheel was first documented as being used in Mesopotamia

Mathematics

2 answers:

Lilit [14]3 years ago

4 0

Answer:

5,172 years

Step-by-step explanation: it the answer

vlada-n [284]3 years ago

4 0

5,172 years long

<em>Hope it helps...</em>

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What is( 5×100)+(6x10)+(8×1/10)+(9×1/1,000) in standard form

nadya68 [22]

Answer:

6x^10+2504/5+(9*1/1,0)

Step-by-step explanation:

Hope this helps :)

5 0

3 years ago

DOES ANYONE KNOW THE ANSWER ???? Please I can’t fail this test !

Zigmanuir [339]

Answer:

The last option

Step-by-step explanation:

You take the middle 2 numbers, add them up, and divide by 2.

6 0

2 years ago

A ladder is placed against a wall such that the top is 8 feet above the ground. If the ladder is 10 feet long, how far away from

Annette [7]

Answer:

6 feet

Step-by-step explanation:

Consider the right triangle formed by the wall, ladder and ground.

Let the distance the ladder is from the wall be d , then

Using Pythagoras' identity in the right triangle

The square on the hypotenuse ( ladder) is equal to the sum of the squares on the other 2 sides ( wall and d ), then

d² + 8² = 10²

d² + 64 = 100 ( subtract 64 from both sides )

d² = 36 ( take the square root of both sides )

d = $\sqrt{36}$ = 6

That is the ladder is 6 feet away from the wall

7 0

3 years ago

A fishing store gives customers 10 new lures for every 2 fishing poles they buy. How

Firlakuza [10]

Answer:

40 lures

Step-by-step explanation

First, 10 for every 2 means multiplication. 2 goes into 8 4 times. 4x2=8

10 lures multiplied by 4 is 40.

I hope this helps! ツ

3 0

3 years ago

Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap

bazaltina [42]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)$

$A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

<em>The circumference of a quarter of circle is equal to</em>

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)$

$C=6\pi\ cm$

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

$AC=\sqrt{12^2+12^2}$

$AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

6 0

3 years ago