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GarryVolchara [31]
3 years ago
15

3/4 + 2/5= adding different denominator

Mathematics
2 answers:
Anastasy [175]3 years ago
7 0
I hope this helps with the problem
ASHA 777 [7]3 years ago
4 0

1. Make both denominators equal you need to multiply the numerator & denominator by the same number

3/4 *5

2/5 *4

2. After they are made the same you can just add the numerators together

15/20 + 8/20 = 23/20

3. Then you can simplify the answer in this case you can leave it as an improper fraction or change it to a mixed

1  3/20

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Answer:

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4 years ago
The factorization below is missing two positive integers a and b. 6x^(3)+18x^(2)-240x=6x(x-a)(x+b) Factor the polynomial and the
Dvinal [7]

Answer:

a = 5

Step-by-step explanation:

Hello, please consider the following.

6x^3+18x^2-240x=6x(x^2+3x-40)\\\\\text{** The sum of the zeroes is -3=-8+5 and the product is -40=-8*5. **}\\\\\text{** So, we can factorise. **}\\\\6x^3+18x^2-240x=6x(x^2+3x-40)=6x(x^2+8x-5x-40)\\\\=6x(x(x+8)-5(x+8))\\\\\large \boxed{=6x(x+8)(x-5)}

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Thank you.

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4 years ago
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If n = 1, the right hand side is equal to 2*1 = 2 and the left hand side is equal to 1^1 + 1 = 1 + 1 = 2

Assume that the relation holds for any value of n.

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3 years ago
Ill give brainiest for this question :D<br> (its not multiple choice)
Ipatiy [6.2K]

Answer:

see explanation

Step-by-step explanation:

Given

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(b)

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