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Romashka [77]
2 years ago
9

Help me please number 3 and 5 ​

Mathematics
2 answers:
ziro4ka [17]2 years ago
6 0

Answer:

Step-by-step explanation:

(3)

U=180-123=57

69+57+?=180

?=54

(5)

B=180-143=37

49+37+?=180

?=94

wolverine [178]2 years ago
4 0

Answer:

3. 54  | 5. 94

Step-by-step explanation:

3.) 123-69=54 to get the inside number.

5.) 143-49=94 to get the inside number.

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Will 5x-3y>15 have a solid line
marysya [2.9K]

Answer:

The inequality 5x-3y >15 have a dashed line

Step-by-step explanation:

we have

5x-3y >15

The solution of this inequality is the shaded area below the dashed line

The equation of the dashed line is 5x-3y=15

The slope of the dashed line is positive

The y-intercept of the dashed line is -5 ---> point (0,-5)

The x-intercept of the dashed line is x=3 ----> point (3,0)

Graph the solution

see the attached figure

6 0
3 years ago
Identify the function shown in the graph
hram777 [196]

Answer:

C

Step-by-step explanation:

The line crosses the y-axis at 3, and has a slope of -1/5. You can use the formula y=mx+b where m represents the slope and b is the point at which the line crosses the y-axis.

3 0
3 years ago
Read 2 more answers
A biased coin has a probability of 0.4 of coming up heads. What is the probability that when flipped one hundred times it comes
inn [45]

Using the binomial probability relation ; the probability that an head is obtained at least 50 times is 0.0271

<u>Using the binomial probability relation</u> :

  • P(x = x) = nCx * p^x * q^(n-x)
  • p = probability of success = 0.4
  • q = 1 - p = 0.6
  • n = number of trials = 100

P(x ≥ 50) = p(x = 50) + p(x = 51) + ...+ p(x = 100)

<u>Using a binomial probability calculator</u> :

P(x ≥ 100) = 0.0271

Therefore, the probability that atleast 50 heads are obtained in the trial is 0.0271

Learn more :brainly.com/question/12474772

5 0
3 years ago
A walking path across a park is represented by the equation y = -3x - 6. A
Brrunno [24]
I think y=-3x - 6 is right
5 0
2 years ago
Which equation represents a hyperbola with a center at (0, 0), a vertex at (−48, 0), and a focus at (50, 0)?
Sedbober [7]
<span>The center, vertex, and focus all lie on the line y = 0. Then we know that the equation of a hyperbola is a^2 + b^2 = c^2 . a^2 represents the x part of the equation and the y part will be subtracted. We know that the vertex is 48 units from the center and that the focus is 50 units from the center. Then we have that b^2 = 2500 - 2304 = 196 . Thus the equation that represents the hyperbola is x^2/2304 - y^2/196 = 1 or 49x^2 -576y^2 - 112896 = 0</span>
8 0
2 years ago
Read 2 more answers
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