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andrezito [222]
3 years ago
12

Four friends are trying to decide what kind of cake to order for a party: cheesecake, chocolate, or yellow. Everyone was asked t

o vote for their favorite, and the winner under the unknown voting method was chocolate. Upon calling the store, they found out that the store was out of yellow cake. They decide to recalculate the winner given this new information, and the winning cake is cheesecake. Which fairness criterion has been violated in this election
Mathematics
1 answer:
Zepler [3.9K]3 years ago
5 0

Step-by-step explanation:

I think chocolate fairness criterion has been violated because under the unknown voting method the winner was chocolate but upon calling the store they ordered for yellow cake not chocolate

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What expression has the same value as 3\5|9
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Answer:

6/10/18

Step-by-step explanation:

Because all I did was multiply each number by two and you would still get the same answer

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The Johnson twins were born eleven years after their older sister. This​ year, the product of the three​ siblings' ages is exact
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So there are 3 siblings: the first twin, the second twin, and their older sister.

Since the sister is older by 11 years, you can represent their relationship with the following equation;
age of twin = age of older sister - 11
t = s - 11

Representing this next part may be a little hard to show, but i'll do my best :)

Adding the ages together can be represented like this;
total age = t + t + s
If the product of their ages ( t * t * s ) is 1181 more than the sum, you can show it like this:
t * t * s = (t + t + s) + 1181
Now you substitute in (s - 11) for t because s = t - 11.
t * t * s = (t + t + s) + 1181\\
(s-11) * (s-11) * s = ((s-11) + (s-11) + s) + 1181\\
(s^{2}-22x+121)*s=s+s-11-11+1181\\
s^{3}-22s^{2}+121s-2s=1159\\
s^{3}-22s^{2}+118s-1159=0
Factor:
Since it's a third-degree equation, I just entered it into a polynomial solver in my calculator. There was only one factor listed, x = 19. Using (s - 19) = 0 as a factor, the equation becomes the following:
s^{3}-22s^{2}+118s-1159=0\\
(s-19)(s^{2}-3s+61)=0
Using the quadratic formula, you get:
s= \frac{-b(+-)\sqrt{b^{2}-4ac}}{2a}\\
s= \frac{-(-3)(+-)\sqrt{(-3)^{2}-4(1)(61)}}{2*1}\\
s= \frac{3(+-)\sqrt{(9)-244}}{2}\\
s= \frac{3(+-)\sqrt{-235}}{2}

Since you have a square root of a negative number, the answer will be imaginary. You cannot have an age that is imaginary, so the age of the older sister (s) is 19 years.

Because t = s - 11, that means that t = (19) - 11 = 8.
t is the age of the twins, so the twins are 8 years old.
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