It is 2 lol also use a calculator it’s wayyy easier this is like the easiest equation every
A)
Let x represent the cost of 1 student, and y the cost of 1 teacher.
B)
In the first group, there's 25 students and 2 teachers. Their total cost is $97.50
So 25x + 2y = 97.50
In the second group, there's 32 students and 3 teachers. Their total cost is $127
So 32x + 3y = 127
We get the following system of equations:
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)
C)
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)
In equation (1)
25x + 2y = 97.50
25x + 2y - 2y = 97.50 - 2y
25x = 97.50 - 2y
25x / 25 = 97.50/25 - 2y/25
x = 3.9 - (2/25)y
In equation (2), let's replace x by its algebraic value
32x + 3y = 127
32(-2/25y + 3.9) + 3y = 127
11/25y + 124.8 = 127
11/25y + 124.8 - 124.8 = 127 - 124.8
11/25y = 2.2
(11/25y) / (11/25) = 2.2 / (11/25)
y = 5
x = -2/25y + 3.9
x = -2/25 * 5 + 3.9
x = 3.5
So the cost of each student is $3.5, and the cost of each teacher is $5.
Hope this helps! :)
Answer: The discounted price is $948. The value of the discount itself is $632.
Step-by-step explanation:
<h3>To calculate discounts, you multiply the percentage of the discount as a decimal with the price of the product.
In this particular case:
0.40 [percentage of discount] x $1580 [original cost] = $632 (the amount of the discount) </h3><h3>$1580 - $632 = $698 [new price after discount is applied]</h3>
![x^{ \frac{m}{n} }= \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%20%7D%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20)
![x^{ \frac{1}{2} }= \sqrt[2]{x^1}](https://tex.z-dn.net/?f=x%5E%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%3D%20%5Csqrt%5B2%5D%7Bx%5E1%7D%20)
or √x