What is the equation of the line that has a slope of 3 and passes through the point (1, -2)

Help will give the brain crown or whatever it is!!!

dolphi86 [110]

Answer:

A will be 5 and B will be 25

8 0

2 years ago

What’s the answer? Some say 9, others say 1

zmey [24]

The answer should be 9.

After you solve what's in the parentheses, you solve the problem starting from left to right.

6÷2(1+2)
6÷2(3)
3(3)
9

8 0

2 years ago

Read 2 more answers

Can someone please help mee (will give brainliest 20 points!!!)

Mice21 [21]

[a] x = 175 - 7.5p

For a, we are isolating the x variable to one side of the equation.

0.4x + 3p = 70

0.4x = - 3p + 70

x = - 7.5p + 175

[b] x = 115

For b, we are solving for x when p = 8.

x = - 7.5p + 175

x = - 7.5(8) + 175

x = 115

7 0

1 year ago

Given m

kenny6666 [7]

Answer:

Step-by-step explanation:

Given, 

m || n

So,

35° = y° [Alternate interior angles]

And,

y° + x° = 180° [Since linear pair]

=> x + 35 = 180

=> x = 180 - 35

=> x = 145°

Hence, 

x = 145°, y = 35°

6 0

2 years ago

Read 2 more answers

Write an equation (a) in slope-intercept form and (b) in standard form for the line passing through (-3,5) and parallel to x + 4

Dmitry [639]

Answer:

$\boxed{\sf Standard-form :x + 4y -17=0 }\\$

$\boxed{\sf Slope-intercept\ form :y =\dfrac{-1}{4}x +\dfrac{17}{4}}$

Step-by-step explanation:

Here a equation of the line is given to us and we need to find out the equation of line which passes through the given point and parallel to the given line , the given equation is ,

$\longrightarrow x + 4y = 7\\$

Firstly convert it into slope intercept form of the line which is y = mx + x , as ;

$\longrightarrow 4y = -x + 7 \\$

$\longrightarrow y =\dfrac{-x}{4}+\dfrac{7}{4}\\$

On comparing it to y = mx + c , we have ,

$\longrightarrow m =\dfrac{-1}{4}\\$

$\longrightarrow c =\dfrac{7}{4}\\$

Now as we know that the slope of two parallel lines is same . Therefore the slope of the parallel line will be ,

$\longrightarrow m_{||)}=\dfrac{-1}{4}\\$

Now we may use point slope form of the line as ,

$\longrightarrow y - y_1 = m(x-x_1) \\$

On substituting the respective values ,

$\longrightarrow y - 5 =\dfrac{-1}{4}\{ x -(-3)\}\\$

$\longrightarrow y -5=\dfrac{-1}{4}(x+3)\\$

$\longrightarrow 4(y -5 ) =-1(x +3) \\$

$\longrightarrow 4y -20 = - x -3 \\$

$\longrightarrow x + 4y -20+3=0\\$

$\longrightarrow \underset{Standard \ Form }{\underbrace{\underline{\underline{ x + 4y -17=0}}}} \\$

Again the equation can be rewritten as ,

$\longrightarrow y - 5 = \dfrac{-1}{4}(x +3) \\$

$\longrightarrow y = \dfrac{-1}{4}x -\dfrac{3}{4}+5 \\$

$\longrightarrow y = \dfrac{-1}{4}x -\dfrac{20-3}{4} \\$

$\longrightarrow \underset{Slope-Intercept\ form }{\underbrace{\underline{\underline{ y =\dfrac{-1}{4}x +\dfrac{17}{4}}}}}\\$

6 0

1 year ago