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3 years ago

I NEED HELP FOR THESE PROBLEMS.

Mathematics

2 answers:

stepan [7]3 years ago

7 0

Answer:

1. 25%

2. very likely that school will stay open tmr

3. what do the variables stand for?

5. not proportional

6. proportional

Step-by-step explanation:

zaharov [31]3 years ago

4 0

Answer:

1. 25%

2. 19/20 (This is a fraction btw)

3. I don't know this question sorry :(

5. No

6. Yes

Step-by-step explanation:

Have a good day :)

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2 years ago

Each week, Christian earns $x fixing bicycles and receives $10 as his allowance. To find how much he will earn in total over 2 w

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2 years ago

Based on a poll, 60% of adults believe in reincarnation. Assume that 5 adults are randomly selected, and find the indicated p

vlabodo [156]

Answer:

There is a 25.92% probability that exactly 4 of the selected adults believe in reincarnation.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they believe in reincarnation, or they do not believe. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

There are 5 adults, so $n = 5$

60% believe in reincarnation, so $p = 0.6$

What is the probability that exactly 4 of the selected adults believe in reincarnation?

This is P(X = 4).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{5,4}.(0.6)^{4}.(0.4)^{1} = 0.2592$

There is a 25.92% probability that exactly 4 of the selected adults believe in reincarnation.

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3 years ago