Answer:
17.89 :)
Step-by-step explanation: hii
Answer:
A) The value of a is <u>29</u>.
B) The value of b is <u>greater than 29</u>.
C) In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
D) The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
Step-by-step explanation:
Solving for Part A.
Given,

We have to solve for a.

By using addition property of equality, we will add both side by 9;

Hence the value of a is <u>29</u>.
Solving for Part B.
Given,

We have to solve for b.

By using addition property of inequality, we will add both side by 9;

Hence the value of b is <u>greater than 29</u>.
Solving for Part C.
In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
Solving for Part D.
The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
I would use a proportion
51.03/88% = x/100%
Which is saying: if 51.03 is 88% of the number, what is 100% of the number
Cross multiply to get x=57.99
Area ( If you know the circumference) :
C^2 / (4×3.14) Brackets are important!
So you have to type :
53.38^2/(4×3.14)
= 226.865
Right. Your answer is still no because your x-value needs to be positive.