Csc theta=-2 then theta equals csc^-1(-2) then theta would equal 5pi/6, 7pi/6
Answer : option A
To find the range of scores that represents the middle 50 % of the student who took the test , we find inter quartile
Inter quartile range is the middle 50% of the given range of scores.
The difference between the upper quartile and lower quartile is the inter quartile that is middle 50%
From the diagram , we can see that
Upper quartile = 89
lower quartile = 65
So range is 65% to 89%
Answer:
x=-2 y=7
Step-by-step explanation:
