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Vinvika [58]
3 years ago
13

In your notebook, set up the following subtraction in a vertical format and select the correct answer. Find 2p 2 3p - 4 less - 2

p 2 - 3p 4. 4p2 6p 8 4p2 - 6p - 8 4p2 6p - 8 0.
Mathematics
1 answer:
Elena L [17]3 years ago
3 0

The equation in the reduced form of the equation is \rm 4p^ 2 + 6p - 8.

Given that,

Equation; \rm  2p^ 2 + 3p - 4\  by\  -2p ^2 - 3p +4

We have to reduce the equation.

According to the question,

To reduce the equation means we need to subtract one equation from the other.

To determine the reduced form of the equation following all the steps given below.

Equation; \rm  2p^ 2 + 3p - 4\  by\  -2p ^2 - 3p +4

Subtraction equation 1 from equation 2,

\rm  = \rm  2p^ 2 + 3p - 4\  -(-2p ^2 - 3p + 4)\\\\=  2p^ 2 + 3p - 4\  -(-2p ^2 -3p +4)\\\\ = 2p^ 2 + 3p - 4+2p^ 2 + 3p - 4 \\\\ = 4p^ 2 + 6p - 8

Hence, The equation in the reduced form of the equation is \rm 4p^ 2 + 6p - 8.

For more details refer to the link given below.

brainly.com/question/1807316

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HACTEHA [7]

Given:

The expression is

2\dfrac{1}{3}-1\dfrac{2}{5}

To find:

The error in Frankie's work.

Solution:

We need to simplify 2\dfrac{1}{3}-1\dfrac{2}{5}, so

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2\dfrac{1}{3}=2\dfrac{5}{15}

and,

1\dfrac{2}{5}=-1\dfrac{2}{5}\times \dfrac{3}{3}

1\dfrac{2}{5}=-1\dfrac{6}{15}

Now,

2\dfrac{1}{3}-1\dfrac{2}{5}=2\dfrac{5}{15}-1\dfrac{6}{15}

2\dfrac{1}{3}-1\dfrac{2}{5}=(2+\dfrac{5}{15})-(1+\dfrac{6}{15})

2\dfrac{1}{3}-1\dfrac{2}{5}=2+\dfrac{5}{15}-1-\dfrac{6}{15}

2\dfrac{1}{3}-1\dfrac{2}{5}=1-\dfrac{1}{15}

2\dfrac{1}{3}-1\dfrac{2}{5}=\dfrac{14}{15}

Therefore, there is error in Frankie's last step. In that step, he did not subtract the mixed fraction correctly.

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Did I do this correctly?
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