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patriot [66]
3 years ago
11

3. Find the products.a) (a? + 4) (a? – 4)​

Mathematics
1 answer:
Stolb23 [73]3 years ago
7 0

Answer:

a^2-16

Step-by-step explanation:

you just a.a+a.-4+4.a+4.-4=a^2-16

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i can see it

Step-by-step explanation:

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One angle of a right triangle measures 8°. What is the measure of the other acute angle?
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  82°

Step-by-step explanation:

The acute angles in a right triangle are complementary. The other one is ...

  90° -8° = 82°

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Which is the domain of y=10-2x^
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The sum of G and the qoutient of 3 and h
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3 years ago
What is the inverse and restricted domain of the equation 8x^2-3
kari74 [83]

Answer:  \bold{y=\pm \dfrac{\sqrt{2(x+3)}}{4},\qquad x\neq -3}

<u>Step-by-step explanation:</u>

y = 8x² - 3            (Restriction: none -  x is All Real Numbers)

The inverse is when you swap the x's and y's and then solve for y

x = 8y² - 3            <em>swapped the x and y</em>

x + 3 = 8y²           <em>added 3 to both sides</em>

\dfrac{x+3}{8}=y^2           <em>divided both sides by 8</em>

\sqrt{\dfrac{x+3}{8}}=\sqrt{y^2}           <em>square rooted both sides</em>

\pm \sqrt{\dfrac{x+3}{8}}=y           <em>simplified</em>

\pm \sqrt{\dfrac{x+3}{8}\bigg(\dfrac{2}{2}\bigg)}=y           rationalized the denominator

\pm \sqrt{\dfrac{2(x+3)}{16}}=y           <em>simplified</em>

\pm \dfrac{\sqrt{2(x+3)}}{4}=y           <em>simplified</em>

<u>Restriction:</u>

The radical <em>(inside the square root sign)</em> cannot be negative

→  2(x + 3) ≥ 0

      x + 3 ≥ 0         <em>divided both sides by 2</em>

      x       ≥ -3         <em>subtracted 3 from both sides</em>



4 0
3 years ago
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