Answer:
The statistic for this case would be:

And replacing we got:

Step-by-step explanation:
For this case we have the following info:
represent the sample size
represent the number of employees that earn more than 50000

We want to test the following hypothesis:
Nul hyp. 
Alternative hyp : 
The statistic for this case would be:

And replacing we got:

And the p value would be given by:

First, find the slope using the equation, y2 - y1 / x2 - x1
1-5 / 4 - - 4 = -4/8 = -1/2
plug this into slope intercept form
y = -1/2x + b
Next use one of the points to find b using point-slope form. I will use (4,1)
y - y1 = m ( x - x1)
y - 1 = -1/2 (x - 4)
y -1 = -1/2x + 2
+1 +1
y = -1/2x + 3 is your equation
Answer:
A, B, C, E, and F
To solve this problem, you should make sure to find the equation first. Start by doing rise/run with your two given points on the graph. From the point (-1,1) you rise 4 and then run 16 over to the point (3,2). That gives us a slope of 4/16 which can then be simplified to 1/4. That means that letter F tells us the equation of the line is y= 1/4x + 5/4.
From there you want to check your points, (3,2) and (-1,1). The first number is always x and the second number is always y. So you plug the point numbers into the equation we just found to see if they work. In the photos I inserted are how to do this step.
Once you have checked your points and you know for sure they're solutions, that gave you letters A and B. Since the point (1, 3/2) is also given in one of the answers we should check that point as well. (Also done in one of the photos) Since the point came out correctly that gives us letter C and also tells us there is more than 2 solutions. This means that letter E is also correct.
Hope this helped!
Answer:

And replacing we got:

So we are going to expect about 2,85 automobiles for this case.
Step-by-step explanation:
For this case we define the random variable X as "number of automobiles lined up at a Lakeside Olds dealer at opening time (7:30 a.m.)" and we know the distribution for X is given by:
X 1 2 3 4
P(X) 0.05 0.30 0.40 0.25
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete
For this case we can calculate the epected value with this formula:

And replacing we got:

So we are going to expect about 2,85 automobiles for this case.
509 people.


you can't have 0.094 of someone so we round the answer off the 509.