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elena55 [62]
3 years ago
15

8 15 27 blank 20 find the blank number​

Mathematics
1 answer:
777dan777 [17]3 years ago
6 0

Answer:

the blank number is 23

Step-by-step explanation:

8, 15, 27, x, 20

common ratio, r= T2÷ T1= T3÷ T2

= 15 ÷ 8 =27÷ 15

= 1.8 = 1.8

20 ÷ x = x ÷ 27

( cross multiply,)

x²= 540

x =√540

x = 23.24

x = 23

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(a-2)^3+8   = a^3-8+8 = a^3

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 <span>(b-2)^3+8  = b^3-8+8 = b^3


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3 years ago
A cooler has a temperature of 32 degrees Fahrenheit. A bottled drink is placed in the cooler with an initial temperature of
FinnZ [79.3K]

Answer:

k \approx 0.44

Step-by-step explanation:

Given function:

f(t) = (ce)^{-kt}+32

As per question statement:

Initial temperature of bottle is 70 ^\circ F.

i.e. when time = 0 minutes, f(t) = 70 ^\circ F

70 = ce^{-k\times 0}+32\\\Rightarrow 38 = ce^{0}\\\Rightarrow c = 38

After t = 3, f(t) = 42^\circ F

42 = 38 \times e^{-k\times 3}+32\\\Rightarrow 42-32 = 38 \times e^{-3k} \\\Rightarrow 10  = 38 \times e^{-3k} \\\Rightarrow e^{3k} = \dfrac{38}{10}\\\Rightarrow e^{3k} = 3.8\\\\\text{Taking } log_e \text{both the sides:}\\\\\Rightarrow log_e {e^3k} = log_e {3.8}\\\Rightarrow 3k \times log_ee=log_e {3.8}   (\because log_pq^r=r \times log_pq)\\\Rightarrow 3k \times 1=log_e {3.8}\\\Rightarrow 3k = 1.34\\\Rightarrow k = \dfrac{1.34}{3}\\\Rightarrow k \approx 0.44

Hence, the value is:

k \approx 0.44

8 0
3 years ago
How to calculate concentration with just the absorbance and % transmittance measurements from a spectrometer? ​
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Answer:

A=ε*l*c

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There is a linear relationship between the concentration of a sample and absorbance according to Beer-Lambert Law.

A=ε*l*c

where;

A=absorbance

ε=absorption coefficient

l=path length

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Because % transmittance is transmittance value multiplied by 100 then, the equation that will allow us calculate absorbance from % transmittance value will be;

A= 2- log₁₀ % T where T is transmittance.

8 0
3 years ago
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klasskru [66]
You need the Least Common Multiple of 12 and 9.

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2 years ago
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djverab [1.8K]

Answer:

Volume: 41.643

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