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kicyunya [14]
3 years ago
5

3. Three model greenhouses are shown below. They are made by covering the tops and sides of a wood frame with plastic. The botto

m of the green house is not covered with plastic. Of the three models, which has the greatest amount of plastic needed to make it and which has the least amount of plastic needed? 3 ft ) 5 ft 5 ft 5 ft 3111/ 8 ft 6 ft 6 it 8 ft 8 ft 6 ft 8 ft Model A 12 ft Model B 10 ft Model C​
Mathematics
1 answer:
dmitriy555 [2]3 years ago
5 0

Answer:

New Materials Have Made Greenhouses Less ... In our garden, we recently had a major ... Besides the trends mentioned above, there are many ... Since seasonal rains will not reach your greenhouse plants, you need to ... Glass and clear plastic function in basically the ...

Step-by-step explanation:

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An employee compiled sales data for a company once each month. The scatter plot below shows the sales (in multiples of $1000) fo
svp [43]

Answer:

940

Step-by-step explanation:

The scatter plot below shows the sales (in multiples of $1000) for the company over time (in months).

Also the sales can be modeled by the help of a linear function as:

y = 0.94x + 12.5.

Now we know that the company's sales increase per month is the slope of the linear function by which this situation is modeled.

We know that for any linear function of the type:

y=mx+c

'm' represents the slope and 'c' represents the y-intercept of the line.

Hence, by looking at the equation we get:

m=0.94

but as the sales are multiplied by 1000.

Hence,

0.94×1000=$ 940.

Hence, the company's sales increase per month is:

$ 940

5 0
2 years ago
Let sin A= -3/5 with 270°&lt; A&lt; 360°. Find the following.<br> sin A/2
GREYUIT [131]

Answer:

1/sqrt10

Step-by-step explanation:

1) Find out cosA using formula (cosA)^2+(sinA)^2=1

The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5

So cosA=-4/5 or cosA=4/5.

Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.

2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.

(sinA/2)^2= 0.1

sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10

But 270°< A< 360°, then 270/2°<A/2<360/2°

135°<A/2<180°, so sinA/2 must be positive and the only correct answer is

sin A/2= 1/sqrt10

6 0
2 years ago
∫c<br> x sin y ds, C is the line segment from (0, 1) to (3, 5)
Mnenie [13.5K]
Parameterize the line segment C by

\mathbf r(t)=\langle x(t),y(t)\rangle=(1-t)\langle0,1\rangle+t\langle3,5\rangle=\langle3t,1+4t\rangle

where t\in[0,1]. Then

\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt
\mathrm ds=\|\langle3,4\rangle\|\,\mathrm dt
\mathrm ds=5\,\mathrm dt

So the integral is

\displaystyle\int_Cx\sin y\,\mathrm ds=5\int_0^1x(t)\sin y(t)\,\mathrm dt
=\displaystyle5\int_0^13t\sin(1+4t)\,\mathrm dt
=\dfrac{15}{16}(\sin5-\sin-4\cos5)\approx-2.7516
3 0
3 years ago
What is the median of this set of data: 593, 588, 540, 434, 420, 398, 390, 375.
alexandr402 [8]

Answer:

B. 427

Step-by-step explanation:

The median is the middle number. When you cross out numbers on the list you end up with 420 and 434. We take the average:

(420 + 434)/2 = 427

5 0
3 years ago
Read 2 more answers
Dy/dx = y/x , y(1) = −2
s2008m [1.1K]

Start with

\dfrac{dy}{dx}=\dfrac{y}{x}

Separate the variables:

\dfrac{dy}{y} = \dfrac{dx}{x}

Integrate both parts:

\displaystyle \int \dfrac{dy}{y} = \int\dfrac{dx}{x}

Which implies

\log(y) = \log(x)+c

Solving for y:

y = e^{\log(x)+c} = e^{\log(x)}e^c=xe^c

Since e^c is itself a constant, let's rename it c_1.

Fix the additive constant imposing the condition:

y(1) = c_1\cdot 1 = -2\iff c_1=-2

So, the solution is

y(x) = -2x

5 0
3 years ago
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