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lana66690 [7]
2 years ago
14

Hey guys please help if I did this question correct if not can you answer it for me I would give you a Brainliest answer if you

answer and that is NO JOKE❤​

Mathematics
1 answer:
S_A_V [24]2 years ago
4 0
Your answers seem correct. they are logical
You might be interested in
Which method would be more efiicient to solve the system y=1/2x and 2x+3y=28
Licemer1 [7]
Probably the subsitution method


y=1/2x
subsitute that fr y

2x+3(1/2x)=28
2x+3/2x=28
times 2 both sides
4x+3x=56
7x=56
divide by 7 both sides
x=8
sub back

y=1/2x
y=1/2(8)
y=4

(x,y)
(8,4)
6 0
3 years ago
Hi, can someone help me pretty please?
Tju [1.3M]
It’s 174 square feet
3 0
2 years ago
Read 2 more answers
Find the area of each figure. Round to the nearest tenth. Use 3.14 or 22/7
sertanlavr [38]

Answer:

d. 28.3

Step-by-step explanation:

Given

Radius ( r) = 3 m

Area of the circle

= π r²

= 3.14 * 3* 3

= 28.26

= 28.3 ft²

3 0
3 years ago
Algebra help?<br><br> 343 = (x/6) ^2/3
Vladimir79 [104]

I can only assume that you meant, "Solve for x:"

Apply the exponent 3/2 to both sides of this equation.  The result will be

     3/2

343 = x/6.    

Multiplying both sides by 6 isolates x:

          3/2

6*343           = x                         Since 7^3 = 343,  the expression for x

                                                  can be rewritten as

           3/2

6*(7^3)          =   x                      which can be further simplified, as follows:


x =  6^(3/2)*7^(9/2), or:

x = 6^(3/2)*7^(8/2)*√7, or

x = 6^(3/2)*7^4*√7

3 0
4 years ago
During the first part of a​ trip, a canoeist travels 18 miles at a certain speed. the canoeist travels 4 miles on the second par
storchak [24]
We can set it up like this, where <em>s </em>is the speed of the canoeist:

\frac{18}{s} + \frac{4}{s-5} = 3

To make a common denominator between the fractions, we can multiply the whole equation by s(s-5):

s(s-5)[\frac{18}{s} + \frac{4}{s-5} = 3] \\ 18(s-5)+4s=3s(s-5) \\ 18s - 90+4s=3 s^{2} -15s

If we rearrange this, we can turn it into a quadratic equation and factor:

18s - 90+4s=3 s^{2} -15s \\ 22s-90=3 s^{2} -15s \\ 3 s^{2} -37s+90=0 \\ (3s-10)(s-9)=0 \\ s= \frac{10}{3} ,9

Technically, either of these solutions would work when plugged into the original equation, but I would use the second solution because it's a little "neater."  We have the speed for the first part of the trip (9 mph); now we just need to subtract 5mph to get the speed for the second part of the trip.

9-5 = 4

The canoeist's speed on the first part of the trip was 9mph, and their speed on the second part was 4mph.
5 0
3 years ago
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